The sample space is:
(1, 1); (1, 2) - sum of 3; (1, 3); (1, 4); (1, 5) - sum of 6; (1, 6);
(2, 1) - sum of 3; (2, 2); (2, 3); (2, 4) - sum of 6; (2, 5); (2, 6);
(3, 1); (3, 2); (3, 3) - sum of 6; (3, 4); (3, 5); (3, 6) - sum of 9;
(4, 1); (4, 2) - sum of 6; (4, 3); (4, 4); (4, 5) - sum of 9; (4, 6);
(5, 1) - sum of 6; (5, 2); (5, 3); (5, 4) - sum of 9; (5, 5); (5, 6);
(6, 1): (6, 2); (6, 3) - sum of 9; (6, 4); (6, 5); (6, 6)
Answer:
0.8753
Step-by-step explanation:
Calculate the probability that your job will be ready before 10.01 am
Here, the parameter of an Exponential is E(X)=12
Now, to calculate the third job probability, it follows Poisson Distribution with parameter 1/λ
Therefore, E(Y) =1/12
Here, The third job will be ready for 10:01 AM, then E(Y)=61/12
Therefore, the required probability is
=1- POISSON(3,5,true)
=1-0.1246
=0.8753