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stellarik [79]
3 years ago
9

If the interest on investment is $44 when the interest rate is 5%. find the interest when the rate is 8.4%.

Mathematics
1 answer:
kolezko [41]3 years ago
6 0
The interest at 8.4% is:
44\times\frac{8.4}{5}=73.92
The answer is $73.92.
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What is 4.3(v+2.5)=8.11+4v
True [87]

Answer:

-8.8

Step-by-step explanation:

We begin by simplifying the parenthesis through multiplication. Parenthesis is a structure which signals multiplication happening.

4.3(v+2.5)=8.11+4v\\4.3v+10.75=8.11+4v

We now begin combining like terms across the equal sign by performing the inverse or doing the opposite. Move first the 8.11 by subtracting it from both sides.

4.3v+10.75-8.11=8.11-8.11+4v\\4.3v+2.64=4v

Now, move 4.3v across by subtracting it from both sides.

4.3v-4.3v+2.64=4v-4.3v

2.64=-0.3v

Finally, we divide both sides by the coefficient of v.

\frac{2.64}{-0.3} =\frac{-0.3v}{-0.3} \\-8.8=v

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3 years ago
Solve for u in terms of s, t, and v. <br> t = u + s + v
harina [27]

Answer:

t = u + s + v \\  \boxed{u = t - s - v}

  • <u>u = t-s-v</u> is the right answer.
7 0
2 years ago
Help will give brainlyest
bazaltina [42]
X=-9 is that answer
5 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
Borrows £10,000 over 5 years simple interest rate of 15%
zysi [14]

Answer:

{ \tt{simple \: interest = p \times r \times t}} \\  = 10000 \times 15\% \times 5 \\  = £7500

8 0
3 years ago
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