<em>Answer:</em>
<em />
<em>x³ + x² - 6x = 0</em>
<em>x(x² + x - 6) = 0</em>
<em>x(x² + 3x - 2x - 6) = 0</em>
<em>x[x(x + 3) - 2(x + 3)] = 0</em>
<em>x(x - 2)(x + 3) = 0</em>
<em>x₁ = 0</em>
<em>x - 2 = 0 => x₂ = 2</em>
<em>x + 3 = 0 => x₃ = - 3</em>
Answer:
child's ticket = 4.75 adult ticket=10.75.
Step-by-step explanation:
The cost of an adult ticket is 6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is 40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
Therefore the cost of a child's ticket (c) is 4.75 and the cost of an adult ticket (c+6) is 10.75.
The probability of 1 number showing up out of 20 is 1/20
The probability of 3 different numbers showing up would be 3/20
Answer: 3/20
16x² - 8x + 1 = (4x)² - 2 · 4x · 1 + 1² =(4x - 1)²
Used: (a - b)² = a² -2ab + b²