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Mathematics

1 answer:

lyudmila [28]4 years ago

7 0

Answer:

-2, 6

Step-by-step explanation:

(x - 6)(x + 2) = 0

x - 6 = 0 x+ 2 = 0

x = 6 x = -2

The values of x that would result in the given expression being equal to 0, in order from least to greatest, are -2 and 6.

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What is the value of n such that the expression x² + 11x + n is a perfect square trinomial? a. 11. b. 25. c. 30. d.25. e.36

lapo4ka [179]

Answer:

The value of n is 30.25.

Step-by-step explanation:

The given expression is

$x^2+11x+n$ ....(1)

The perfect square trinomial are defined as

$(x+y)^2=x^2+2xy+y^2$ .....(2)

On comparing (1) and (2), we get

$2y=11$

$y=\frac{11}{2}$

The given expression is perfect square trinomial if

$n=y^2$

$n=(\frac{11}{2})^2$

$n=\frac{121}{4}$

$n=30.25$

Therefore the value of n is 30.25.

5 0

3 years ago

Read 2 more answers

Graph the following line: -2x + 6y = 12

Naddik [55]

X=6 y=4
$-2x + 6y = 12$

3 0

3 years ago

A circle centered at the origin contains the point (0,-9). Does (8, sqr 17) also lie on the circle?

Reptile [31]

Check the picture below.

since the circle is centered at the (0,0) origin, and a point on it is at (0, -9), its radius is simple the distance between those two, or r = 9.

if the second point is also on the circle, it must also be 9 units away from the origin.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{\sqrt{17}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(8-0)^2+(\sqrt{17}-0)^2}\implies d=\sqrt{8^2+(\sqrt{17})^2} \\\\\\ d=\sqrt{64+17}\implies d=\sqrt{81}\implies d=9~~\textit{\Large \checkmark}$