Answer:
D is the closest, but look at the work below.
Step-by-step explanation:
First let's write what we know.
We have 8 equal sections, they are:
                             1
                      5          2
                  1                     1
                      4          3
                             1
We need to find the probability the pointer will land on an odd-numbered section. 
Now we find how many odd numbered sections there are. 
                            <em> </em><u><em>1</em></u>
                      <u><em>5</em></u>          2
                  <u><em>1</em></u><u><em> </em></u>                    <em><u>1</u></em>
                      4          <u><em>3</em></u>
                             <u><em>1</em></u>
There are 6 odd numbered sections.
So you have a 6 in 8 chance of spinning an odd number or 6/8.
6/8 can be reduced to 3/4 or .75 05 75%
This doesn't match any of your answers you gave, so double check the question or the answers. D is the closest, but this is a very clear solution and I am wondering if there is an oops somewhere.