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Zepler [3.9K]
3 years ago
11

Female III-4 is pregnant via male III-5. The owner of this breeding pair wants to know the probabilities of several possible out

comes for their offspring (IV-3). If you need help with how to approach calculating these probabilities, use the Hint.
Mathematics
1 answer:
faust18 [17]3 years ago
6 0

Answer: the following are required for IV-3 to have condition

Explanation:

-II-4 passes an X b chromosome to III-4 (probability = 1/2).

-If III-4 has the genotype X B X b (accounted for by the above probability), then she passes an X b chromosome to IV-3 (probability = 1/2).

-III-5 passes a Y chromosome to IV-3 (probability = 1/2).

All of these requirements are needed in sequence, so you apply the product rule here, too (1/2 x 1/2 x 1/2 = 1/8).

Once the individual probabilities are known, the sum and/or product rules can be used for various combinations (both conditions, either condition, etc.).

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There are 5000 sweets 24% blue 5% green 17% red rest are orange find percentage of orange
ss7ja [257]

Answer: 54%

Step-by-step explanation:

24+17+5=46

100-46=54

5 0
3 years ago
A tessellation is the regular _____ of a plane shape.
KIM [24]
A tessellation is the regular t<span>iling of a plane shape</span>
4 0
3 years ago
Help me pleaseeeee?!
den301095 [7]

Answer:

#1: -1.5, -0.5, 1/2, 1.5

#2:  -3, -1, 1.2, 2.3

Step-by-step explanation:

#1

First we have to figure out the correct order before we plot.

Find the biggest number:

looking at the number the biggest would be 1.5

Find the smallest number:

Looking at the number the smallest would be -1.5

Now that we have that we can easily figure out the rest...

(Going from least to greatest; like on a number line)

-1.5, -0.5, 1/2, 1.5 (That is how you will place the first one)

#2

(Use the steps from above to find the answer)

Biggest: 2.3

Smallest: -3

Order: -3, -1, 1.2, 2.3 (Placing on number line use that order)

Hope this helps :)

8 0
2 years ago
The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l
Burka [1]
Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N
5 0
2 years ago
Help please , 20 points
alex41 [277]
The top-left one because 3ba is the same as 3ab
8 0
2 years ago
Read 2 more answers
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