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Shalnov [3]
3 years ago
12

George has a small coin collection.  He has collected 16 gold coins, 28 silver coins, 32 copper coins, and4 bronze coins. At a f

lea market, George sells 15% of his coins. Find the number of coins he sold.
Mathematics
2 answers:
katovenus [111]3 years ago
8 0
16+28+32+4
44+32+4
76+4
80

\frac{15}{100}
0.15

80*0.15
12

12 coins
alekssr [168]3 years ago
8 0
This problem  can easily confuse people who are easily confused.

It makes absolutely no difference how many of each kind of coin he had. The
only important fact is that he had (16 + 28 + 32 + 4) = 80 coins all together.

He sold 15% of them.  ' 15% ' means ' 0.15 ', and ' of ' means ' times '.

0.15 x 80 = <u>12 coins sold.</u>


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Answer:

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

Step-by-step explanation:

Given

n = 200

x_1 = 34 -- City C

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Required

Determine the 90% confidence interval

This is calculated using:

CI = \bar x \± z\frac{\sigma}{\sqrt n}

Calculating \bar x

\bar x = \bar x_1 - \bar x_2

\bar x = \frac{x_1}{n} - \frac{x_2}{n}

\bar x = \frac{34}{200} - \frac{54}{200}

\bar x = 0.17 - 0.27

For a 90% confidence level, the ​z-score is 1.65.  So:

z = 1.65

Calculating the standard deviation \sigma

\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }

So:

\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }

\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}

So:

CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

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Answer:

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Step-by-step explanation:

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