Hello!
Mode :

Given observations are :-
22,40,21,18,47,22,19
Now , mode =

The answer is 22 as it appears two times in the given set of observations.
Hope this is clear :)
Have a good day:)
Answer:
Janies' monthly pocket money is $180.
Step-by-step explanation:
Janies' adjusted monthly pocket money:
Initial pocket money = $150
Ratio of new pocket money = 6:5
Let his new pocket money be represented by x,
x:$150 = 6:5
$150 x 6 = x (5)
$900 = 5x
x = 
x = $180
Therefore, Janies' monthly pocket money is $180.
{2x+y=11
{-x+2y=2 //*2
{2x+y=11
+
{-2x+4y=4
5y=15
y=3
-x+6=2
x=4
Answer
x=4; y=3
Answer:
a)0.7
b) 10.03
c) 0.0801
Step-by-step explanation:
Rate of return Probability
9.5 0.1
9.8 0.2
10 0.3
10.2 0.3
10.6 0.1
a.
P(Rate of return is at least 10%)=P(R=10)+P(R=10.2)+P(R=10.6)
P(Rate of return is at least 10%)=0.3+0.3+0.1
P(Rate of return is at least 10%)=0.7
b)
Expected rate of return=E(x)=sum(x*p(x))
Rate of return(x) Probability(p(x)) x*p(x)
9.5 0.1 0.95
9.8 0.2 1.96
10 0.3 3
10.2 0.3 3.06
10.6 0.1 1.06
Expected rate of return=E(x)=sum(x*p(x))
Expected rate of return=0.95+1.96+3+3.06+1.06=10.03
c)
variance of the rate of return=V(x)=![sum(x^2p(x))-[sum(x*p(x))]^2](https://tex.z-dn.net/?f=sum%28x%5E2p%28x%29%29-%5Bsum%28x%2Ap%28x%29%29%5D%5E2)
Rate of return(x) Probability(p(x)) x*p(x) x²*p(x)
9.5 0.1 0.95 9.025
9.8 0.2 1.96 19.208
10 0.3 3 30
10.2 0.3 3.06 31.212
10.6 0.1 1.06 11.236
sum[x²*p(x)]=9.025+19.208+30+31.212+11.236=100.681
variance of the rate of return=V(x)=sum(x²*p(x))-[sum(x*p(x))]²
variance of the rate of return=V(x)=100.681-(10.03)²
variance of the rate of return=V(x)=100.681-100.6009
variance of the rate of return=V(x)=0.0801
The factors of a number are all whole numbers that can be multipled to get that number.
1, 2, 4, 8, 16, 32, 64