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ella [17]
4 years ago
8

If UT is a midsegment of QRS, find SQ.

Mathematics
1 answer:
serg [7]4 years ago
8 0
If UT is a midsegment,
  SR = 2·UT
  7x-1 = 2(3x+1)
We can add 1-6x to solve this
  x = 3

Then the length SQ is twice the length of SU.
  SQ = 2(2x+2) = 2(2·3+2)
  SQ = 16
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Since there are already choices in the question, I suggest you just substitute in the values of x to each choice and check whether the corresponding value for y appears. This is also called the trial and error method in multiple choice.

The answer that represents the data in the table is C. <span>y = x^2 – 5.</span>
3 0
3 years ago
Satellites KA-1212 and SAL-11 have spotted a UFO. Scientists want to determine its distance from KA-1212 so they can later deter
ch4aika [34]

Answer:

The distance of UFO from KA-1212 is 1229.7 km.

Step-by-step explanation:

We are given that,

Distance between the satellites = 900 km

Angle made by the satellite KA-1212 = 60°

Angle made by the satellite SAL-11 = 75°

So, from the figure below,

The third angle is given by = 180° - (60°+75°) = 180° - 135° = 45°

Then, using the law of sines, we have,

\dfrac{x}{\sin 75}=\dfrac{900}{\sin 45}\\\\x=\dfrac{900\times \sin 75}{\sin 45}\\\\x=\dfrac{900\times 0.966}{0.707}\\\\x=\dfrac{869.4}{0.707}\\\\x=1229.7

<h3>Thus, the distance of UFO from KA-1212 is 1229.7 km.</h3>

6 0
3 years ago
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Which of the following is not a solution of 10 &gt; x – 7y?
ASHA 777 [7]
D.
10>(12)-7(0)

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7 0
3 years ago
Find the distance from point A to the given line.
VMariaS [17]

Answer:

Let's see what to do buddy...

Step-by-step explanation:

_________________________________

Step (1)

To find the distance between the line which formed like :

ax + by + c = 0

and the point which is like :

h =  \binom{m}{n}  \\

we use following equation :

d =  \frac{ |a(m) + b(n) + c| }{ \sqrt{ {a}^{2} +  {b}^{2}  } } \\

_________________________________ Step (2)

y =  - x + 4

x + y - 4 = 0

So ;

a = 1

b = 1

c =  - 4

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

A = ( 2 , - 1 )

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

So we have :

d =  \frac{ | \: 1(2) + 1( - 1) - 4| }{ \sqrt{ {1}^{2} +  {1}^{2}  } } =  \\

d =  \frac{ |2 - 1 - 4| }{ \sqrt{1 + 1} } =  \frac{ | - 3| }{ \sqrt{2} }  \\

d =  \frac{3}{ \sqrt{2} } \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

5 0
3 years ago
Find the slope of the line passing through the points (-18, -5) and (-19, -13)​
LuckyWell [14K]

Answer:

Let (-18, -5) be (x1,y1)

(-19, -13) be (x2,y2)

slope = (y2-y1)/(x2-x1)= (-13+5)/(-19 +18) = 8

8 0
4 years ago
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