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3 years ago

Please help!!!!! I don't just want the answer I would like someone to walk me through the process or just explain. Thanks!!!

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

Answer: $51{\circ}$

Step-by-step explanation:

The law of sines says that in a triangle ABC with sides a,b and c respectively we have :-

$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$

Now , for the given triangle in the picture we have

$\frac{\sin 104^{\circ}}{15}=\frac{\sin J}{12}\\\\\Rightarrow \sin J=\frac{\sin 104^{\circ}\times12}{15}\\\\\Rightarrow \sin J=\frac{0.97029572627\times12}{15}\\\\\Rightarrow \sin J=0.776236581016\\\\\Rightarrow J=\sin^{-1}(0.776236581016)=50.91728017\approx51{\circ}..............[\text{Using calculator}]$

Hence, the measure of angle J = $51{\circ}$

adoni [48]3 years ago

5 0

Sin J / 12 = Sin 104 / 15

Set a proportion:

Sin J * 15 = Sin 104 * 12
Sin J = .77

< J = 51.9

J equals 51.9, answer d

Answer would be: CHOICE D

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The table gives the probability distribution of the number of dvds sold per day at a music store. what is the probability of 5 o

nikklg [1K]

Let x represents the number of dvds sold per day:
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3 years ago

According to the University of Nevada Center for Logistics Management, 6% of all merchandise sold in the United States gets retu

jeka57 [31]

Answer:

$p_v =P(z>3.390)=0.000349$

If we compare the p value and the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of returns at the Houston store is significantly higher than 0.06 or 6%.

Step-by-step explanation:

1) Data given and notation n

n=80 represent the random sample taken

X=12 represent number of items returned

$\hat p=\frac{12}{80}=0.15$ estimated proportion of items returned

$p_o=0.06$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that proportion of returns at the Houston store was more than the national expectation (0.06):

Null hypothesis: $p\leq 0.06$

Alternative hypothesis: $p >0.06$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.15 -0.06}{\sqrt{\frac{0.06(1-0.06)}{80}}}=3.390$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.390)=0.000349$

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3 years ago

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xeze [42]

Answer: The answers are stated below

Step-by-step explanation: Attached below is the explaination of the solution.