Answer:


Step-by-step explanation:
Absolute Value Inequality entered :
|y+2|>6
Step by step solution :
Step 1: Rearrange this Absolute Value Inequality
Absolute value inequalitiy entered
|y+2| > 6
Step 2: Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |y+2|
For the Negative case we'll use -(y+2)
For the Positive case we'll use (y+2)
Step 3: Solve the Negative Case
-(y+2) > 6
Multiply
-y-2 > 6
Rearrange and Add up
-y > 8
Multiply both sides by (-1)
Remember to flip the inequality sign
y < -8
Which is the solution for the Negative Case
Step 4: Solve the Positive Case
(y+2) > 6
Rearrange and Add up
y > 4
Which is the solution for the Positive Case
Step 5:
Wrap up the solution
y < -8
y > 4
Solutions in Interval Notation
(-∞,-8)
(4,+∞)
Solutions on the Number Line
Two solutions were found :
y > 4
y < -8
Simliar-AA is your answer
We are given with the variable cost which is:
q = -20s + 400
The selling price is 's'. So, the profit can be represented by:
P = qs - q(12)
Subsituting:
P = (-20s + 400)s - 12 (-20s + 400)
P = -20s^2 + 640s - 4800
To optimize this, we must differentiate the equation and equate it to zero, so:\
dP/ds = -40s + 640 = 0
Solving for s,
s = 16
So, the selling price should be $16 to optimize the yearly profit.
Answer:
it's
2.08
Step-by-step explanation:
<em><u>
</u></em>
<em><u>so</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>think</u></em><em><u> </u></em><em><u>think</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u>f</u></em><em><u>u</u></em><em><u>l</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em>2</em><em>.</em><em>0</em><em>8</em>
2 because according to the Oxford dictionary I have scan