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guapka [62]
4 years ago
6

How do I solve this ? Help ASAP!!! Steps please

Mathematics
2 answers:
mixer [17]4 years ago
8 0

Answer:

1x + 4

Step-by-step explanation:

add like terms

6x - 3x - 2x = 1x or x then you are left with 4

elena-14-01-66 [18.8K]4 years ago
3 0

Answer:

Step-by-step explanation:

start by gathering all the x together.

6x-3x-2x=1x

what you have left is 1x+4=?x+?

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If a line has an x-intercept at =
kotykmax [81]

Answer:

y = 5/3x - 5

Step-by-step explanation:

y = mx + b

b = y-intercept

m = slope

y = mx - 5

<u>plug in the x-intercept</u>

0 = m(3) - 5

5 = 3m

m = 5/3

y = 5/3x - 5

graph is below, both intercepts are on the line

4 0
3 years ago
Can someone help me with this ASAP please ​
Serjik [45]

Answer:

it should be 50

Step-by-step explanation:

because 2x5 = 10 yes and 50 + 10 = 60 correct me fi im wrong

4 0
3 years ago
Read 2 more answers
Number 5-103 I can't figure out how to do the proportions web
Neko [114]

Serena !  Where did you get the 86.8 ?

You divided 434 by 5 ! 

That was exactly the right thing to do, but you didn't know
what you had because you got messy and dropped the units.

What you actually divided was

               (434 candy) divided by (5 minutes).

If you kept the units in your calculation, as you always should do,
here's what you would have seen:

                           (434 candy) / (5 minutes)   

                       =    (434 / 5)   candy/minute

                       =        86.8  candy per minute .

I have to confess that I don't know what a proportion web is,
and I actually never heard of it until right now.  So maybe
I shouldn't have tried to answer this question.  But at least
I was able to get the point across to you that you should
ALWAYS keep the units as you go through a calculation.
That message is worth a lot, and it will do you a lot of good.

5 0
3 years ago
Solve the equation 4 sin x - cosec x =cot x for 0° &lt; x &lt; 360°. ​
Dahasolnce [82]

<u>For this question, I will be writing 'csc' instead of 'cosec'</u>

<u />

<u />4\sin x-\csc x=\cot x\\\\4\sin x-\frac{1}{\sin x}=\frac{\cos x}{\sin x}\\\\4\sin^{2} x-1=\cos x\\\\4(1-\cos^{2} x)-1=\cos x\\\\4-4\cos^{2} x-1-\cos x=0\\\\4\cos^{2} x+\cos x-3=0\\\\ (4\cos x-3)(\cos x+1)=0\\\\\cos x=\frac{3}{4}, 1\\\\\therefore \boxed{\cos^{-1} \left(\frac{3}{4} \right), 180^{\circ}, 360^{\circ}-\cos^{-1} \left(\frac{3}{4} \right)}

3 0
2 years ago
Kim performed a transformation on rectangle ABCD to create rectangle A'B'C'D', as shown in the figure below: A(-1,2) B(-1,5) C(-
AysviL [449]

Answer:

C) Reflection across the x-axis.

Step-by-step explanation:

From Linear Algebra we define the reflection across the x-axis is for P(x,y) =(x,y):

P'(x,y) = (x, -y) (1)

If we know that A(x,y) = (-1, 2), B(x,y) =(-1,5), C(x,y) = (-3, 5) and D(x,y) =(-3, 2), then the reflected points are, respectively:

A'(x,y) = (-1, -2)

B'(x,y) = (-1,-5)

C'(x,y) = (-3,-5)

D'(x,y) = (-3,-2)

In consequence, Kim performed a reflection across the x-axis to create triangle A'B'C'D'. The correct answer is C.

4 0
3 years ago
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