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4 years ago

6

The expression 1500(1.14)t represents the value of a $1500 investment that earns 14% interest per year, compounded annually for

T years. what is the value of a $1500 investment at the end of five years?

1 answer:

Ipatiy [6.2K]4 years ago

8 0

I need a bad bleep uh Addison Rae

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a sales clerk wants to make at least $519 . If he makes a base salary of $335 and $10.25 per hour at his part time job how many

Katen [24]

Answer:

50 hours

Step-by-step explanation:

50 hours because you have to divide 519 from 10.25 and doing all of that you will get 50

7 0

3 years ago

Evaluate the following expression,<br> 5x [7+ (10-2) + 4)

strojnjashka [21]

Answer: 95x

Step-by-step explanation: Remove parentheses. 5x(7+10-2+4)

Add 7 and 10.

5x(17-2+4)

Add 15 and 4.

5x multiped by 19

Multiply 19 by 5

95x

5 0

3 years ago

Helen wants to buy a dictionary that costs $7, a dinosaur book that costs $16, and a children's cookbook that costs $17. She has

Hitman42 [59]

Answer:

Helen requires 15$ more to buy the three books.

Step-by-step explanation:

We are given the following in the question:

Cost of dictionary = $7

Cost of dinosaur book = $16

Cost of cook book = $17

Helen's allowance = $25

Total cost of three books =

$=7 +16+17\\=\$ 40$

Extra money required to buy three books =

$=40-25\\=\$15$

Thus, Helen requires 15$ more to buy the three books.

8 0

4 years ago

Marilyn saves 30% of the money she earns each month.She earns $350 each month.How much does she save?

Delicious77 [7]

Answer:

$245

Step-by-step explanation:

Savings percent= $350 × 30%

=$350 × 30/100

= $105

Money saved= $350- $105

= $ 245

6 0

3 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0

3 years ago