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Ahat [919]
2 years ago
9

Guys i need help please

Mathematics
1 answer:
klio [65]2 years ago
5 0
I would help but I’m not sure how, please do not press that link or else it will track your address! <33
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Please answer it would help me a lot
Deffense [45]
Find if all the ratios are proportional to 1:8. 2:16 is, so is 3:24, and 4:32. 4.5*8=36, and 5:40 is proportional. 6:48 is, and 6.5*8=52. The table is proportional, just divide the pay by the hours and you should be getting 8.
5 0
3 years ago
Flying against the wind, a jet travels 5760 miles in nine hours flying with the wind, the same jet travels 5000 miles in five ho
aalyn [17]

Answer:

Step-by-step explanation:

9h+5h(5h-5760)-2+12=y

7 0
3 years ago
Isabel graphed the following system of equations.
igor_vitrenko [27]

Answer:


Step-by-step explanation:

Simplified the following system of equations into a linear equation.

Graphed (plot the points) the linear equation onto the graph.

To get the solution (2,-2) (x,y)she went positive 2 to the right and -2 down.


4 0
3 years ago
B. The 100th term of 60, 110, 160, ... is (Simplify your answer.) How to do this?​
Advocard [28]

The 1st term is 60.

Add 50 to this to get the 2nd term, 60 + 50 = 110.

Add 50 to that to get the 3rd term, 110 + 50 = 160.

Add 50 to that to get the 4th term, 160 + 50 = 210.

And so on...

Notice that in the 2nd term, we added 1 copy of 50 to the 1st term.

In the 3rd, we ultimately added 2 copies of 50 to the 1st term.

In the 4th, we added 3 50s.

And so on... If the pattern continues, then the <em>n</em>-th term can be obtained by adding (<em>n</em> - 1) copies of 50 to the first term.

So, the 100th term is

60 + (100 - 1) * 50 = 5010

5 0
3 years ago
11. Which matrix represents the system of equations below?
dimulka [17.4K]

Answer:

\left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]

Step-by-step explanation:

The system of equations is;

-12x-13y +13z =15

7x-10y-3z = 11

7x+14y +5z = -5

The coefficient matrix is \left[\begin{array}{ccc}-12&-13&13\\7&-10&-3\\7&14&5\end{array}\right]

The constant matrix is \left[\begin{array}{c}15\\11\\-5\end{array}\right]

The augmented matrix is \left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]

4 0
3 years ago
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