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Ahat [919]
3 years ago
9

Guys i need help please

Mathematics
1 answer:
klio [65]3 years ago
5 0
I would help but I’m not sure how, please do not press that link or else it will track your address! <33
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Answer: 30miles traveled 80 miles

Step-by-step explanation:

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Equation of a line with slip of 5 passing through points (-4,-6)
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\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=5[x-(-4)] \\\\\\ y+6=5(x+4)\implies y+6=5x+4\implies y=5x-2

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3 years ago
Maria found the least common multiple of 6 and 15. Her work is shown below. Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 6
sineoko [7]
She totally missed seeing the number 30, as 15 x 2 is 30 and 6 x 5 is 30. 30 is her LCM
4 0
3 years ago
Read 2 more answers
The volume of a sphere is 3,000 m^3. What is the surface area of the sphere to the nearest square meter?
vovangra [49]

Answer:

C

Step-by-step explanation:

V=4 /3πr3

3000=1 1/3*3.14*r*r*r

3000=4.18666667*r*r*r

716.560509=r^{3}

Cube root the number

8.94851471456=r

TSA=4\pir^{2}

TSA=4*3.14*8.94851471456*8.94851471456

TSA=1006.26

Since we used different numbers for pi and I rounded our answer will be different but the answer is C

3 0
3 years ago
A ball is launched upward from a height 40 feet above ground level. The ball’s height at t seconds is given by -16t^2=128=40 .
Nesterboy [21]

Answer:

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

Step-by-step explanation:

<u><em>The correct question is</em></u>

A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?

we have

h(t)=-16t^{2}+128t+40

so

For h(t)=100 ft

substitute in the equation and solve for x

-16t^{2}+128t+40=100

-16t^{2}+128t-60=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+128t-60=0

so

a=-16\\b=128\\c=-60

substitute in the formula

x=\frac{-128(+/-)\sqrt{128^{2}-4(-16)(-60)}} {2(-16)}

x=\frac{-128(+/-)\sqrt{12,544}} {-32}

x=\frac{-128(+/-)112} {-32}

x=\frac{-128(+)112} {-32}=0.5

x=\frac{-128(-)112} {-32}=7.5

therefore

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

7 0
4 years ago
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