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3 years ago

Find the measure of x. X = -1 X = 9 X = 13

Mathematics

1 answer:

Ivan3 years ago

3 0

Answer:

x = 7

Step-by-step explanation:

Given that ∠PRQ = 135°

therefore ∠ QRS = 180 - 135 = 45° (both the 2 adjacent angles sit on the straight line)

Since ∠ QRS = 45°

therefore ∠RST = 45° ( They are alternate angles)

Since ∠RST = 45°

therefore ∠UST = 180 - 45 = 135° (both the 2 adjacent angles sit on the straight line)

∠UST = 135°

∠UST = 15(x + 2)

therefore,

15(x + 2) = 135

x + 2 = 9

x = 7

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anygoal [31]

Hi:)
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3 years ago

Read 2 more answers

Find the equation of the line passing through the point (–1, 5) and perpendicular to the line y = – 3x + 4.

dsp73

9514 1404 393

Answer:

A) 3y = x + 16

Step-by-step explanation:

The equation of a perpendicular line can be found by swapping the x- and y-coefficients and negating one of them. The constant will be chosen to match the given point.

Swapping coefficients, we get ...

-3y = x + c

Negating the y-coefficient gives ...

3y = x + c

Filling in the given point, we have ...

3(5) = -1 + c

16 = c

The equation of the perpendicular line can be written as ...

3y = x + 16 . . . . matches choice A

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Note that choice A is the only equation that gives a line with positive slope. The given equation has negative slope, so its perpendicular must have positive slope.

3 0

3 years ago

Evaluate 2x - y + 4z, if x = 1, y = 2 and z = -1

lidiya [134]

2 x 1 - 2 + 4 x -1 =

the answer is -4.

5 0

3 years ago

Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda

pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

Step-by-step explanation:

Given equation is

$x^2y'' - 9xy+24y=0$

This Euler Cauchy type differential equation.

So, we can let

$y=x^m$

Differentiate with respect to x

$y'= mx^{m-1}$

Again differentiate with respect to x

$y''= m(m-1)x^{m-2}$

Putting the value of y, y' and y'' in the differential equation

$x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0$

$\Rightarrow m(m-1)x^m-9mx^m+24x^m=0$

$\Rightarrow m^2-m-9m+24=0$

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

$y_1(x)=x^4$

and

$y_2(x)=x^6$

First we compute the Wronskian

$W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|$

$= \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|$

=x⁴×6x⁵- x⁶×4x³

=6x⁹-4x⁹

=2x⁹

≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

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3 years ago

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Lana71 [14]

Speed is distance over time

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perhaps i am misunderstanding something?

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3 years ago