All categories

3 years ago

How many numbers have an absolute value of 6

Mathematics

2 answers:

Tatiana [17]3 years ago

5 0

Answer:

Search web.

Web results= absolute value of 6 is 6.

Step-by-step explanation:

dangina [55]3 years ago

4 0

Answer:

Step-by-step explanation:

Hope this helps

You might be interested in

Can someone give me answers pls asap

GuDViN [60]

Answer:

answers are:

1) 1.75

2) 1.25

6 0

3 years ago

What is co efficient of -9xy2z

Radda [10]

The coefficient of ALL variables is the number in front of the variable, which here its -9

8 0

3 years ago

(2x + 3) + (4x + 5)<br> please help im really confused

luda_lava [24]

Answer: it's 6x + 8 if you solve it

8 0

3 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago

In an isosceles triangle, one angle is 75° greater than each of the other two equal angles. Find the measure of all three angl

mote1985 [20]

It's 35, 35, and 110

8 0

3 years ago