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3 years ago

Solve the given inequality and graph the solution on a number line.

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

$-\dfrac{x}{2}+\dfrac{3}{2} < \dfrac{5}{2}\ \ \ \ |\cdot2\\\\-x+3 < 5\ \ \ |-3\\\\-x < 2\ \ \ \ |change\ the\ signs\\\\x > -2\to x\in(-2;\ \infty)$

Answer\ in\ attachment.

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Find the volume and tell me if cavalieri's principle applies to the figure<br> Need answer ASAP

Volgvan

Where are the numbers or just this? We need numbers like 1 0 6

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3 years ago

Laura has 160 pounds of green beans at her vegetable stand. If she sells 10 pounds of green beans every hour, what is the percen

Mademuasel [1]

Given:

Laura has 160 pounds of green beans at her vegetable stand.

She sells 10 pounds of green beans every hour.

To find:

The percent decrease in green beans after 3 hours.

Solution:

We have,

Beans sold in 1 hour = 10 pounds

So, Beans sold in 3 hours = 30 pounds

Decrease in green beans after 3 hours is 30 pounds.

Now,

$\%\text{Decrease}=\dfrac{\text{Decrease in green beans after 3 hours }}{\text{Initial amount of green beans}}\times 100$

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$\%\text{Decrease in green beans after 3 hours}=18.75\%$

Therefore, the correct option is A.

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3 years ago

I need help with part b and A So can anyone tell me how to solve this?

tekilochka [14]

Answer:

A:
You do 65 divided by 25 = 2.6
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2 years ago

Read 2 more answers

A, B and C lie on a straight line.

horsena [70]

Here you go, i added a bit of explanation as to why i used the numbers to help you understand the method :)

6 0

2 years ago

Brainlist<br> Please help me

creativ13 [48]

Answer:

Yes she made an error. Explanation is below.

Step-by-step explanation:

Let the sample space for a six sided number cube be S

$n(S) = \{1,2,3,4,5,6\}\\n(S) = 6$

Let the event of a number getting greater than two be B

$n(B) = \{3,4,5,6\}\\n(B) = 4$

To find:

the probability of complement of B that is

p(~B) = ?

Solution"

First we need to solve probability for number getting greater than two

$p(B) = \frac{n(B)}{n(S)}$

Now substituting the values we get

$p(B) = \frac{4}{6}$

$p(B) = \frac{2}{3}$

but we need complement of B so

$p(\textrm{complement of B)} = 1 - p(B)\\p(\~B) = 1 - p(B)\\p(\~B) = 1 - \frac{2}{3}\\ =\frac{1}{3} \\$

P(complement of rolling a number greater than two) = $\frac{1}{3}$

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3 years ago