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Alisiya [41]
3 years ago
15

A reflection and a glide are the same thing. True or false?

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0
I think its fqalse sure thio
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4. Kevin is using his scanner to make a smaller version of the school logo to put in the yearbook.
vredina [299]

Answer:

scale factor 2.5

Step-by-step explanation:

3 0
3 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
Maria found the least common multiple of 6 and 15. Her work is shown below.
Masteriza [31]

Answer:

the lcm would be 30 not 60

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the range for f(x) = 2^x
Natali [406]

Given the function:

f(x)=2^x

The function can also be written as:

y=2^x

The range of the function will be all set of y values.

To find the range, let's graph the function below.

We have:

From the graph above, all possibe y values range from 0 to infinity.

Therefore, the range of the function is from zero infinity.

In interval notation:

Range = (0, +∞)

ANSWER:

4. (0, +∞)

6 0
1 year ago
Find an equation for the inverse for each of the following.
IgorLugansk [536]

Answer:

  • <em>To solve these first swap x and y, solve for y and name it inverse function</em>

3. <u>y = -8x + 2</u>

  • x = -8y + 2
  • 8y = -x + 2
  • y = -x/8 + 2/8
  • y = -(18)x + 1/4

f⁻¹(x) = -(18)x + 1/4

-----------------------------------------

4.<u> y = (2/3)x - 5</u>

  • x = (2/3)y - 5
  • (2/3)y = x + 5
  • y = (3/2)x + (3/2)5
  • y = 1.5x + 7.5

f⁻¹(x) = 1.5x + 7.5

-----------------------------------------

5. <u>f(x) = 2x² - 6</u>

  • x = 2y² - 6
  • 2y² = x + 6
  • y² = 1/2x + 3
  • y = \sqrt{1/2x + 3}

f⁻¹(x) = \sqrt{1/2x + 3}

-----------------------------------------

6. <u>y = (x - 3)²</u>

  • x = (y - 3)²
  • \sqrt{x} = y - 3
  • y = 3 + \sqrt{x}

f⁻¹(x) = 3 +  \sqrt{x}

4 0
3 years ago
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