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zubka84 [21]
3 years ago
6

Find the value of x. 132 (5x + 7) A. 25 B. 45 C. 35 D. 15

Mathematics
2 answers:
loris [4]3 years ago
8 0
A. 25
5x + 7 = 132
5x = 125
x = 5
Agata [3.3K]3 years ago
7 0

Answer:

A.25

Step-by-step explanation:

Both sides of this obtuse angle are the same, which means it has to have the same degrees. If you plug these answer choices into x, it has to equal 132. Thus, 25 was the correct answer.

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Suppose both factors in a multiplication problem are multiples of 10. Why might the number of zeroes in the product be different
Lelu [443]

Answer:

Multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

Step-by-step explanation:

Let the first five multiples of ten be

10*1= 10

10*2= 20

10*3=30

10*4=40

10*5= 50

Suppose we chose 20 and 50.

Now multiplying 20 with 50 we get

20*50= 1000

IF we count the total number of zeros in the factors ( 20 and 50) they are 2.

But the number of zeros in the product (1000) are 3.

This is because when we multiply 2 with 5 we get 10 which adds to the existing number of zeros ( i.e 2) and we get a total of 3 zeros.

And multiplying 10 with 50 we get

10*50= 500

IF we count the total number of zeros in the factors ( 10 and 50) they are 2.

But the number of zeros in the product (500) are also 2.

This is because when we multiply 1 with 5 we get 5 which does not add to the existing number of zeros ( i.e 2) and the total number of zeros remain the same.

Similarly multiplying 20 with 30 we get

20*30= 600

IF we count the total number of zeros in the factors ( 20 and 30) they are 2.

But the number of zeros in the product (600) are also 2.

This is because when we multiply 2 with 3 we get 6 which does not have a zero and the total  number of zeros remain the same as in the factors.

So we see that multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

5 0
3 years ago
Solve the equation x^13-2x^12-x^11+2x^10=0 in the real number system
ASHA 777 [7]

Answer:

x ={0; - 1 ;  2 ;  1}

Step-by-step explanation:

x¹³-2x¹²-x¹¹+2x¹⁰=0

x¹⁰(x³-2x²-x+2)=0

x¹⁰(x+1)(x-2)(x-1)=0

x¹⁰=0    ∨   x+1=0    ∨    x-2=0   ∨   x-1=0

x=0             x= - 1             x= 2          x= 1

3 0
3 years ago
Describe how to find all the points on a baseball field that are equidistant from second base and third base
BlackZzzverrR [31]
This might help explain how to do a very similar problem.... http://www.mathopenref.com/constbisectline.html
8 0
3 years ago
(I need the answer right now please) ΔA'B'C' was constructed using ΔABC and line segment EH. 2 triangles are shown. Line E H is
irina1246 [14]

Answer:

The true statements are

1. BD = DB'

3. m∠EFA = 90°

4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and

   CC'

Step-by-step explanation:

* Lets explain how to solve the problem

- Reflection is flipping an object over the line of reflection.

- The object and its image have the same shape and size, but the

  figures are in opposite directions from the line of reflection

- The objects appear as if they are mirror reflections, with right and left

  reversed

- The line of reflection is a perpendicular bisector for all lines joining

  points on the figure with their corresponding images

- Look to the attached figure for more understand

* Lets solve the problem

- ΔA'B'C' was constructed using ΔABC and line segment EH, where

 EH is the reflection line

- D is the mid-point of BB'

- F is the mid-point of AA'

- G is the mid-point of CC'

* Lets find from the answer the true statements

1. BD = DB'

∵ D is the mid point of BB'

- Point D divides BB' into two equal parts

∴ BD = DB' ⇒ <em>True</em>

2. DF = FG

- It depends on the size of the sides and angles of the triangle

∵ We can't prove that

∴ DF = FG ⇒ <em>Not true</em>

3. m∠EFA = 90°

∵ The line of reflection ⊥ the lines joining the points with their

   corresponding images

∴ EH ⊥ AA' and bisect it at F

∴ m∠EFA = 90° ⇒ <em>True</em>

4. The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC'

- Yes the line of reflection is perpendicular bisectors of them

∴ The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC' ⇒ <em>True</em>

5. ΔABC is not congruent to ΔA'B'C'

∵ In reflection the object and its image have the same shape and size

∴ Δ ABC is congruent to Δ A'B'C'

∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>

4 0
3 years ago
Read 2 more answers
Bob can ride his bike 6.5 miles in 20 minutes what is the rate of speed in miles per hour
vladimir2022 [97]

Answer:

19.5 miles per hour

Step-by-step explanation:

We need to change 20 minutes to hours

1 hours = 60 minutes

20 minutes * 1 hour/60 minutes = 1/3 hour

To find miles per hour we take the miles and divide by hours

6.5 miles

---------------- = 19.5 miles per hour

1/3 hours

7 0
4 years ago
Read 2 more answers
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