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laiz [17]
3 years ago
9

What single transformation is required to map one of these congruent triangles onto the other?

Mathematics
2 answers:
Llana [10]3 years ago
8 0
The answer to your question I think is reflection
Phantasy [73]3 years ago
5 0
The answer is a reflection(:
You might be interested in
*Written Response Question*
belka [17]

The relationship between lines KO and K’O’ is given as Line K'O' = 5 * line KO

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial point to a new location. Types of transformation are<em> reflection, rotation, translation and dilation.</em>

Dilation is the increase or decrease in size of a figure by a scale factor.

The larger figure was dilated using a scale factor of 5, hence:

Line K'O' = 5 * line KO

The relationship between lines KO and K’O’ is given as Line K'O' = 5 * line KO

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

7 0
1 year ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
o-na [289]
This is just cylinder surface area, right? Equation for that would be 2πrh+2πr^2. If we input the data given from the image, it’d be (2 x π x 3.5 x 4)+(2 x π x 3.5 x 3.5). (4 is the height, and I found the radius by dividing the diameter, 7, in half, which is 3.5.) if u plug that into a calculator, u get 164.93.
8 0
2 years ago
Please answer #1 and #2
DIA [1.3K]
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
  y = 2/3(z)(7 - x^2)

2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz

6 0
2 years ago
A sheet of cardboard 12 inches square is used to make an open box by cutting out squares of equal size from the four corners and
GrogVix [38]

Answer:

x=6+3\sqrt{2} is the size of the square

Step-by-step explanation:

Let the side of the square cut from the cardboard be “x”

Size of the square base = 12 -2x, height of the box = x

Volume of square box = Area * height = (12-2x)^2 * x

Differentiating the above equation and equating it to zero, we get –  

d/dx ((12-2x)^2 * x)

d/dx{(144 + 4x^2 -48x)*x}= d/dx (144x + 4x^3 -48x^2)

d/dx (144x + 4x^3 -48x^2) = 0

144+8x^2-96X= 0\\18 +X^2-12X = 0

On solving above equation, we get –  

x=6+3\sqrt{2}  \\ x=6-3\sqrt{2}

5 0
3 years ago
Can someone help with graphs
amm1812

Answer:

here u go..............

5 0
2 years ago
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