So, values of x are: ![x=2\sqrt{15},\,\,x=-2\sqrt{15}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%7B15%7D%2C%5C%2C%5C%2Cx%3D-2%5Csqrt%7B15%7D)
Step-by-step explanation:
We need to find the square root of 5x^2 = 300
Writing in mathematical form:
![5x^2=300](https://tex.z-dn.net/?f=5x%5E2%3D300)
Divide both sides by 5
![\frac{5x^2}{5}=\frac{300}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B5x%5E2%7D%7B5%7D%3D%5Cfrac%7B300%7D%7B5%7D)
![x^2=60](https://tex.z-dn.net/?f=x%5E2%3D60)
Taking square root on both sides
![\sqrt{x^2}=\sqrt{60}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%7D%3D%5Csqrt%7B60%7D)
![x=\pm (\sqrt{2\times 2\times 3\times 5})](https://tex.z-dn.net/?f=x%3D%5Cpm%20%28%5Csqrt%7B2%5Ctimes%202%5Ctimes%203%5Ctimes%205%7D%29)
![x=\pm (\sqrt{2^2 \times 3\times 5})](https://tex.z-dn.net/?f=x%3D%5Cpm%20%28%5Csqrt%7B2%5E2%20%5Ctimes%203%5Ctimes%205%7D%29)
![x=\pm (2\sqrt{3\times 5})](https://tex.z-dn.net/?f=x%3D%5Cpm%20%282%5Csqrt%7B3%5Ctimes%205%7D%29)
![x=\pm (2\sqrt{15})](https://tex.z-dn.net/?f=x%3D%5Cpm%20%282%5Csqrt%7B15%7D%29)
![x=2\sqrt{15},\,\,x=-2\sqrt{15}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%7B15%7D%2C%5C%2C%5C%2Cx%3D-2%5Csqrt%7B15%7D)
So, values of x are: ![x=2\sqrt{15},\,\,x=-2\sqrt{15}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%7B15%7D%2C%5C%2C%5C%2Cx%3D-2%5Csqrt%7B15%7D)
Keywords: Square root
Learn more about square root at:
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Answer:
Step-by-step explanation:
Here is a formula that can help:
Answer:
first one
Step-by-step explanation:
the sum of (9k-4) =3542
so it will be the first one because
28((5+248)/2)=3542
Answer:
I think the answer is 2
Step-by-step explanation:
It is a real number.
A real number is a combination of rational (usually negative) and irrational numbers.
A natural number is a positive integer.
But since -145 is a negative number it can't be a natural number. Making it a real number.
Correct me if I'm wrong.