Answer:
The correct options are 2 and 4.
Step-by-step explanation:
From the given box plot it is clear that
We know that these number divides the data in four equal parts.
25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.
Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.
It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.
Therefore option 3 is incorrect.
The interquartile range is
Therefore option 4 is correct.
The range is
Range = Maximum-Minimum
Therefore option 5 is incorrect.
First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
Answer:
-9/7
Step-by-step explanation:
To find the slope given 2 points, we use the formula
m = (y2-y1)/(x2-x1)
where (x1,y2) and (x2,y2) are the two points
m = (-3-6)/(5--2)
m = (-3-6)/(5+2)
= -9/7
The answer is D because
60 times 5=300
20 times 8=160
25 times 9=225
33 times 10=330
Then add all of them and it gives you $1,015
We know that it costs $68 for 16 square feet of flooring. To find out how much it costs for 12, we first have to find out how much it costs for 1 square foot.
To find that, we would do $68 divided by 16, which is 4.25.
That means 1 square foot costs $4.25.
Then, we would multiply $4.25 by 12 to find how much 12 square feet costs.
$4.25 times 12 is 51.
So, it would cost $51 to have 12 square feet of flooring.
