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lawyer [7]
3 years ago
10

If nelson invests $5000 for 4 years and earns $600, what is the simple interest rate?

Mathematics
1 answer:
klio [65]3 years ago
4 0

Answer: Simple interest rate = 3%.


Step-by-step explanation: We are given invested amount = $5000.

Number of years of investment = 4 years.

Interest earned = $600.

Simple interest formula.

I = P R T.

Where I is the earned interest, P is the invested amount , R is the rate of interest and T is the time in years.

Plugging values in formula, we get

600 = 5000 × R × 4

600 = 20000R.

Dividing both sides by 20000, we get

\frac{600}{20000}  = \frac{20000R}{20000} .

0.03 = R.

Multiplying by 100 to convert it in percentage, we get

0.03 × 100 = R

R = 3 %.



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Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylin
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R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
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a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
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Read 2 more answers
Question 17
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Answer:

698 fishes

Step-by-step explanation:

Generally, we can represent an exponential growth function as;

y = a•(1 + r)^t

originally, there were 3 fishes

The original value in this case means a = 3

After 6 weeks, there were 31

31 in this case is y

r is the increase percentage or rate

t is the time

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31 = 3•(1 + r)^6

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ln 10.33 = 6 ln (1 + r)

ln 10.33/6 = ln (1 + r)

e^0.3892 = (1 + r)

1 + r = 1.476

r = 1.476-1

r = 0.476 or 47.6%

So the growth percentage or rate is 47.6%

For 14 weeks, we simply have the value of t as 14;

So ;

y = 3•(1 + 0.476)^14

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y = 698 fishes

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