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3 years ago

A high school teacher grades a math test. She wants to see the numerical

Mathematics

1 answer:

suter [353]3 years ago

5 0

to see quick score she must use a pie chart

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An equilateral triangle has three congruent sides. If sides are congruent, the opposite angles are congruent.

VladimirAG [237]

Answer:

B)law of detachment

Step-by-step explanation:

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3 years ago

Which of the following items is shaped MOST LIKE the Moon?

Artyom0805 [142]

Answer:

An egg

Step-by-step explanation:

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1 year ago

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The formula F=9/5C+32 is used to convert Celsius to Fahrenheit temperature. If the temperature is 20 C what is it in Fahrenheit?

ahrayia [7]

F = C x 9/5 + 32
(20) x 9/5 + 32
= 68

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3 years ago

On a certain hot summers day, 648 people use the public swimming pool. The daily prices are $1.50 for children and $2.25 for adu

ehidna [41]

Answer:

252 children and 395 adults

Step-by-step explanation:

Make a linear system of equations, where x represents the number of children and y represents the number of adults

x+y=648

1.50x+2.25y=1269

solve using substitution, so y=648-x,

then substitute this into the second equation, so you get 1.50x+2.25(648-x)=1269,

solve for x and you will get x equals the 252

then substitute this into the first equation, so you get 252+y=648

solve and you will get y=395

3 0

3 years ago

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

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3 years ago

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