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Arada [10]
3 years ago
9

Simplifying radicals with variables and exponents

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0
For example, if the question is to simplify square root x^7, you do 7/2=3......1
so the answer would be x^3 times square root x
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There are 92 students that equals 75 how many students are 100 percent
elena-s [515]

Answer:

122.67 or round it to 123

Step-by-step explanation:

i used the butterfly method.

92/75 = x/100.

i multiplied 92*100=9200

then i divided it with 75.

9200/75=x

so the answer is

x=122 or 123

4 0
3 years ago
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Eva is at a sushi restaurant. She ordered 2 pieces of squid for a total of $3.50, 1 piece of eel for $3.25, 3 pieces of tuna for
mixas84 [53]

Answer:

squid, crab, tuna, eel

Step-by-step explanation:

Just make each sushi piece into an equation, then solve it.

For example, for the squid: (s stands for squid)

2s = 3.5\\ s=1.75      Divide both sides by 2 to get "s" by itself

Eel: (e stands for eel)

e = 3.25

Tuna: (t stands for tuna)

3t=6.75\\ t=2.25   Divide both sides by 3 to get "t" by itself

Crab: (c stands for crab)

4c=8\\ c=2       Divide both sides by 4 to get "c" by itself

**Then order from least to greatest**

6 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=1%20%2B%205%20%5Ctimes%206y" id="TexFormula1" title="1 + 5 \times 6y" alt="1 + 5 \times 6y" al
Levart [38]

Answer:

30y+1

Step-by-step explanation:

1+5x6y

1+30y

30y+1

6 0
3 years ago
A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
ss7ja [257]

Answer:

Step-by-step explanation:

Hello!

The researcher wants to test if the valve plates manufactured have the expected tensile strength of 5 lbs/mm. So he took a sample of 42 valve plates and measured their tensile strength, obtaining a sample mean of X[bar]= 5.0611 lbs/mm and a sample standard deviation of S=0.2803 lbs/mm.

The study variable is:

X: tensile strength of a valve plate (lbs/mm)

The parameter of interest is the mean tensile strength of the valve plates, μ.

If the claim is that the valve plates of the sample have on average tensile strength of 5 lbs/mm, symbolically: μ = 5

a) The statistic hypotheses are:

H₀: μ = 5

H₁: μ ≠ 5

b) To determine the critical values and rejection region of a hypothesis test you need three to determine three factors of the hypothesis test:

1) The statistical hypothesis.

2) The significance level.

3) The statistic to use for the analysis.

The statistic hypothesis determines the number of critical values and the direction of the rejection region, in this case, the test is two-tailed you will have two critical values and the rejection region will be divided into two.

With the statistic, you will determine the distribution under which you will work and the significance level determines the probability of rejecting the null hypothesis.

To study the population mean you need that the variable of interest has at least a normal distribution, there is no information about the distribution of the study variable but the sample size is large enough n≥30, so you can apply the central limit theorem to approximate the distribution of the sample mean to normal: X[bar]≈N(μ;σ²/n)

Thanks to this approximation it is valid to use an approximation of the standard normal distribution for the test:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }≈N(0;1)

The critical values are:

Z_{\alpha /2}= Z_{0.05}= -1.648

Z_{1-\alpha /2}= Z_{0.95}= 1.648

You will reject the null hypothesis if Z_{H_0}≤-1.648 or if Z_{H_0}≥1.648

You will not reject the null hypothesis if -1.648<Z_{H_0}<1.648

c)

Z_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }=  \frac{5.0611-5}{\frac{0.2803}{\sqrt{42} } }= 1.41

d) The value of the statistic is between the two critical values so the decision is to not reject the null hypothesis. Then using a significance level of 10% there is no significant evidence to reject the null hypothesis so the valve plates have on average tensile strength of 5 lbs/mm.

e) The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis). If the test is two-tailed, so is the p-value, you can calculate it as:

P(Z≤-1.41) + P(Z≥1.41)= P(Z≤-1.41) + (1 - P(Z≤1.41))= 0.079 + ( 1 - 0.921)= 0.158

p-value: 0.158

I hope it helps!

5 0
3 years ago
HEY CAN ANYONE PLS ASNWER DIS!!!!!1
Ivanshal [37]

Answer:

11 songs

Step-by-step explanation:

first you would multiply 1.80 by 3 which is 5.4

next you would subtract 12.0 by 5.4 and get 6.6

then you would divide 6.6 by .60 to get 11

4 0
3 years ago
Read 2 more answers
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