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stira [4]
4 years ago
8

Use the laws of logarithms and the values given below to evaluate the logarithmic expression (picture provided)

Mathematics
2 answers:
VMariaS [17]4 years ago
5 0

Use the quotient rule [ \text{log}_a\frac{x}{y} = \text{log}_ax-\text{log}_ay ] to simplify.

\text{log}\frac{5}{7} = \text{log}(5)-\text{log}(7)

Simplify using the given values.

0.6990 - 0.8451

-0.1461

Therefore, \text{log}\frac{5}{7}=-0.1461

Best of Luck!

nydimaria [60]4 years ago
4 0

Answer: Option a.

Step-by-step explanation:

To solve the given exercise, you must keep on mind the law of logarithms shown below:

 log(a)-log(b)=log(\frac{a}{b})

Therefore, by applying the law , you can rewrite the expression given, as following:

log(\frac{5}{7})=log(5)-log(7)

You know that:

log5=0.6990\\log7=0.8451

Then, when you substitute values, you obtain:

0.6990-0.8451=-0.1461

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Write the following comparison as a ratio reduced to lowest terms. 169 inches to 13 feet
Elanso [62]

Answer:

14.0833333333 feet | 13 feet

Step-by-step explanation:

169 Inches is 14.0833333333 feet on calculator compared to 13 feet

and 1.08333333333 is 14.0833333333 divided by 13

if is not it, then 13/14.0833333333 is 0.92307692307

i guess that is the lowest terms in ratio

7 0
3 years ago
Suppose y=f(x)+k. what effect does k have on the parent function?
Aleksandr [31]
It moves it up and down

6 0
3 years ago
One of the legs of a right triangle measures 8 cm and its hypotenuse measures 14 cm.
Ugo [173]

Answer:

about 11.5 cm.

Step-by-step explanation:

I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.

8^2+b^2=14^2 simplified: 64+b^2=196

Then, I subtracted 64 on both sides, so I would have "b" by itself.

b^2=132

Next, I found the square root of both b^2 and 132, so I would find the true value of "b."

b=11.4891252931

So, the measure of the other leg rounded to the nearest tenth is about 11.5.

3 0
3 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
3 years ago
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\text{conjugate:\ \boxed{ -3-2i}}
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