Answer:
Explanation:
The O-F glucose test (oxidative-fermentation) is used to determine whether an organism is performs oxidative or fermentative metabolism.
Oxidative metabolism (i.e respiration) takes place in the presence of oxygen while fermentative takes place in the absence of oxygen.
Facultative anaerobes can carry out both fermentation and respiration.
The O-F medium has glucose, peptones and a pH indicator. When the pH of the medium is acidic, that is glucose has been broken down, the medium turns yellow. When it is basic, it turns blue implying that peptone and not glucose had been broken down.
The sealed tube is overlaid with oil so as to prevent oxygen from getting in, making it anaerobic.
The unsealed tube allows oxygen.
Enterics would be yellow is both tubes because they are facultative anaerobes and can grow in the presence or absence of oxygen, hence they carry out both respiration and fermentation.
Answer:
Starch present in A and C, starch not present in B.
Explanation:
Photosynthesis is the process by which plants synthesise sugar.
This process requires light energy, carbon dioxide, and water, and produces sugar and oxygen. This sugar can be turned into starch.
In leaf B, the chemical that absorbs carbon dioxide would mean that there is none in the air for the plant to take in and use for photosynthesis, so it would not make sugar which can be converted to starch.
This is in contrast to C and A, where there is carbon dioxide present in the bag that can be used in photosynthesis.
Answer is b hole this helps
