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2 years ago

Prove that if m, d, and k are integers and d > 0, then (m + dk) mod d = m mod d.

1 answer:

6 0

From the rules of modular arithmetic, (A+B)mod C= (A)modC +(B)modC

So, (m + dk) mod d = (m) mod d+<span> (dk) mod d

clearly </span>(dk) mod d = 0, as one of the things (dk) mod d represents, is the remainder of dk, when divided by d, which is clearly 0.

Thus

(m + dk) mod d = (m) mod d+ (dk) mod d= (m) mod d+ 0=(m) mod d

(m + dk) mod d =(m) mod d

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Find the solution of y = 6x + 1 for x = 5.

Fudgin [204]

The solution is D.
By plugging the x value, 5, into the equation:
6*5=30
30+1=31
y=31
the x value is 5 and the y value is 31
(5, 31)
hope that helps!

7 0

3 years ago

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Jason’s mom gave him 1,000 for his birthday. He put the money in the bank and decides to withdraw 25 per week.

Goshia [24]

Well 1000 for his birthday then subtract 25 each week, w, should be 1000-25w if i am not mistaken.

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3 years ago

1/5 x = 12 plz help im not very good with math

IceJOKER [234]

Answer:

Step-by-step explanation:

1/5x = 12

x = 12 × 5

x = 60

( By using transposing method )

Plz mark it as brainliest

You can recheck it by calculating

60/5= 12

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2 years ago

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Can you guys help me on this math problem

Margarita [4]

I think 47 but i might b wrong lol

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2 years ago

What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a

Anarel [89]

Answer:

Average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: $f(x)= x^2-x-1$

The formula used to find average rate of change is:

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}$

We have, a = -1 and b = 1

Finding f(b) when b=1

$f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1$

Now, finding f(a), when a= -1

$f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1$

Now, putting values and finding average rate of change

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1$

So, average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

4 0

2 years ago