Answer:
The coordinates of point B are (5,-3)
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two points is equal to
![M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
In this problem
Point A is at (-5, -4) and point M is at (0, -3.5)
![point\ A=(x_1,y_1)\\point\ B=(x_2,y_2)\\point\ M=(0,-3.5)](https://tex.z-dn.net/?f=point%5C%20A%3D%28x_1%2Cy_1%29%5C%5Cpoint%5C%20B%3D%28x_2%2Cy_2%29%5C%5Cpoint%5C%20M%3D%280%2C-3.5%29)
substitute in the formula
![(0,-3.5)=(\frac{-5+x_2}{2},\frac{-4+y_2}{2})](https://tex.z-dn.net/?f=%280%2C-3.5%29%3D%28%5Cfrac%7B-5%2Bx_2%7D%7B2%7D%2C%5Cfrac%7B-4%2By_2%7D%7B2%7D%29)
so
Solve for x_2
![0=\frac{-5+x2}{2}\\x_2=5](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B-5%2Bx2%7D%7B2%7D%5C%5Cx_2%3D5)
Solve for y_2
![-3.5=\frac{-4+y_2}{2}\\-7=-4+y_2\\y_2=-3](https://tex.z-dn.net/?f=-3.5%3D%5Cfrac%7B-4%2By_2%7D%7B2%7D%5C%5C-7%3D-4%2By_2%5C%5Cy_2%3D-3)
therefore
The coordinates of point B are (5,-3)
Area of a rectangle is length times width, or base times height (synonymous) In your case you have length of 11ft and a width of 2inches or 2/12 ft, so your area would be 11*(2/12)ft^2 which is (22/12)ft^2, you can simplify this by dividing the numerator and denominator by 2 to give you (11/6)ft^2
Answer:
Option D
Step-by-step explanation:
(8x^2-9y^2-4x) +(x^2-3y^2-7x)
8x^2+x^2-9y^2-3y^2-4x-7x
9x^2-12y^2-11x
Scale for y - 1:1
Scale for x - 1:10
Reason- so that i can plot the points on the graph without any modification to the given one.
Now plot the points on the graph using the scale. I cant obviously do that here.
Answer:
option D
Step-by-step explanation:
The area of a square depends upon the length of its sides
For side a, The area of the square is a²
Therefore a(s) = s²
Therefore, a square of 3 feet has an area of 9 square feet
Option D