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Wewaii [24]
3 years ago
12

What is the probability of rolling a sum of 8 on a standard pair of six-sided dice? express your answer as a fraction or a decim

al number rounded to three decimal places, if necessary?
Mathematics
1 answer:
maxonik [38]3 years ago
7 0
First lets see how many combinations there are that make 8 from the numbers 1-6:

2+6
3+5
4+4
5+3
and 6+2. 

Note: the order does matter, because you roll two die. This means the first die has a number and the second die also has a number. 2 on 1st dice and 6 on 2nd dice would be a different combination than 2 on 2nd dice and 6 on 1st dice.

Now we calculate the probability of getting a number 2 through 6 on the first dice: which is 5/6.

Then calculate the probability of getting a number that pairs up with the first number to make 8: *Note: once you get a number 2 through 6, there is only one other number that you can roll to make 8. This means the probability of getting a match would be 1/6 on the 2nd dice.

Finally, multiply the two fractions we got earlier: 5/6 x 1/6 = 5/36

Your probability would be 5/36 in fraction form, 13.89% in percent form, or 0.139 in decimal form rounded 3 places.

Hope this helps, and May the Force Be With You!

-Jabba the Hut
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3 years ago
Can someone please please help me!!
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Answer:

c

Step-by-step explanation:

7 0
2 years ago
if a fish tank,8/11 of the fish have a red stripe on them.If 16 of the fish have red stripes,how many total fish are in there
Arisa [49]
8/11--------> 16

to find the total number of fish, divide 16 by 8 and multiply it by 11,

16÷8=2
2×11=22

total number of fish= 22

check,

22÷11×8=16

if you want to find the number of fish without the red stripes,

8/11--------> 16
11/11------->22
3/11--------->?

you can either subtract 16 by 22=6
or
22÷11×3=6

hope this helps......
3 0
3 years ago
The community theatre troupe was putting on a summer production of Shakespeare's
Tanzania [10]

Answer:

165

Step-by-step explanation:

since the ticket cost $5.50 per child

so $5.50*30=165

6 0
2 years ago
A Customer Telephone Center receives 1,200 calls in a 24-hour period. Of these calls, 75% occur between 9:30 a.m. and 3:30 p.m.,
Volgvan

Divide Total time into two Time Periods. A regular Demand and a High Demand Time Period. Since 75% of the 1,200 calls occur between 9:30 am and 3:30 pm. We multiply .75 x 1,200 to get 900. We get an average of 900 calls every day between the hours of 9:30 am and 3:30 pm – Our net time for this time period is 6 hours.

Therefore, 6 Hours/900 becomes our quotient

Again, since the denominator is larger we invert it to 900 calls/6 Hours

To get a demand of 150 calls per hour.

We need to be able to handle 150 calls per hour.

So how Many Call Representatives are needed?

Again, our historical data tells us that each person can handle 10 calls an hour.

Therefore 150 calls per hour /10 Minutes = 15 Customer Service Representatives are needed during Peak Time!

Now, Subtract the Peak Hours from the 21 Hours Net Time Per day, gives us 15 Non-Peak hours we have to staff.

8 0
2 years ago
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