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4 years ago

U-3/4=4 please help me ty

Mathematics

2 answers:

Ne4ueva [31]4 years ago

8 0

To solve the equation:

$\frac{u - 3}{4} = 4 \\ \frac{u - 3}{4} \times 4 = 4 \times 4\\ u - 3 = 4 \times 4 \\ u - 3 + 3 = 16 + 3 \\ u = 16 + 3 \\ u = 19$

Therefore, the answer is u=19.

Hope it helps!

const2013 [10]4 years ago

6 0

U-3=16 (multiply both sides by 4)
u=19 (add 3 to both sides)

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Solve using the quadratic formula 2x^2+8x-5=0

Ede4ka [16]

Step-by-step explanation:

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Given,

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a= 1, b= 8, c= -5.

Using formula,

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$x = \frac{ - 8 + - \sqrt{ {8}^{2} - 4 \times 1 \times ( - 5)} }{2 \times 1}$

$x = \frac{ - 8 + - \sqrt{64 + 20} }{2}$

$x = \frac{ - 8 + - \sqrt{84} }{2}$

$x = \frac{ - 8 + - 2 \sqrt{21} }{2}$

Taking negative,

$x = \frac{ - 8 - 2 \sqrt{21} }{2}$

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$x = 4 + \sqrt{21}$

Similarly, taking positive,

$x = \frac{ - 8 + 2 \sqrt{21} }{2}$

$x = \frac{ - 2(4 - \sqrt{21} ) }{2}$

$x = 4 - \sqrt{21}$

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3 years ago

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kirill115 [55]

Answer:

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Step-by-step explanation:

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then you put the y^-5 under the other numbers and make it positive so it becomes:

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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