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3 years ago

U-3/4=4 please help me ty

Mathematics

2 answers:

Ne4ueva [31]3 years ago

8 0

To solve the equation:

$\frac{u - 3}{4} = 4 \\ \frac{u - 3}{4} \times 4 = 4 \times 4\\ u - 3 = 4 \times 4 \\ u - 3 + 3 = 16 + 3 \\ u = 16 + 3 \\ u = 19$

Therefore, the answer is u=19.

Hope it helps!

const2013 [10]3 years ago

6 0

U-3=16 (multiply both sides by 4)
u=19 (add 3 to both sides)

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Jada rode her bike at a constant speed for 3 hours. During that time, she traveled 7.2 miles. What was Jada's riding speed?

NeTakaya

Answer: 2.4 miles per hour

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2 years ago

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3 years ago

Simplify the expression, only odds 9-17

Elodia [21]

All exercises involve the same concept, so I'll show you how to do the first, then you can apply the exact same logic to all the others.

The first thing you need to know is that, when a certain quantity multiplies a parenthesis, you can distribute that number to every element in the parenthesis. This means that

$a(b+c) = ab+ac$

So, $a$ is multiplying the parenthesis involving $b$ and $c$ , and we distributed it: $a$ multiplies both $b$ and $c$ in the final result.

Secondly, you have to know how to recognize like terms, because they are the only terms you can sum. Two terms can be summed if they have the same literal expression. So, for example, you cannot sum $3x+2y$ , and neither $5x^2-4x$ exponents count.

But you can su, for example,

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$23xy^2z^6 - 17xy^2z^6 = 6xy^2z^6$

So, take for example exercise 9:

$1.2(7x-5y) - (10y-4.3x)$

We distribute the 1.2 through the first parenthesis:

$1.2(7x-5y) = 1.2 \cdot 7x - 1.2 \cdot 5y = 8.4x-6y$

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$- (10y-4.3x) = -10y+4.3x$

So, the expression becomes

$8.4x-6y-10y+4.3x$

Now sum like terms:

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3 years ago

Bill hiked 3_10 of a maile and 5 10 th of a mole

julia-pushkina [17]

Yes that's how he walked

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3 years ago

Bharat and ingrid leave their building at the same time on their bikes and travel in opposite directions. If bharat's speed is 1

yanalaym [24]

Answer:

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speed of Bharat = 12kilometers / hour

speed of Ingrid=14 kilometers / hour

For this problem we'll be using formula relating time, distance and speed.i.e

Distance = speed x time

Suppose Bharat is riding at a distance of 'b' kilometers, therefore time taken by him will be:

Time = distance/ speed

Time= b/12 hours.

Also, Ingrid can ride the distance at this time with speed of 14km/hr

The distance would be,

Distance = speed x time

Distance = 14 x (b/12) => 14b/12

Distance= 7b/6

Let ' $d_{b}$ ' be the distance that Bharat have covered after time 't'

therefore, $d_{b}$ = 12 x t

Let ' $d_{i}$ ' be the distance that Ingrid have covered after time 't'

therefore, $d_{i}$ = 14 x t

In order to find the time when they are 78 kilometers apart, we will add $d_{i}$ and $d_{b}$ , because they are travelling in opposite direction creating distance between them.

So,

$d_{i}$ + $d_{b}$ = 78

( 14 x t) + (12 x t) =78

14t + 12t =78

26t= 78

t= 78/26

t= 3hours.

thus, it will take 3 hours until they are 78 kilometers apart

6 0

3 years ago