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Lena [83]
3 years ago
14

What is the surface area of the right cone below?

Mathematics
1 answer:
olga2289 [7]3 years ago
3 0
B. 4967 units idjdnndndndnndndndnndnd
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(x+2)(x-18)=0<br><br>FIND THE SOLUTIONS OF THE EQUATION
vladimir2022 [97]
Either one at any given time could be equal to zero. So
x + 2 = 0
x = - 2

x - 18 = 0
x = 18

I've enclosed a graph of this so you can see that the answers I've given are the ones expected.

6 0
3 years ago
Read 2 more answers
Find the volume of a right prism with height h=10 cm, if :
kozerog [31]

Answer:

Step-by-step explanation:

          So, to begin the altitude of a triangle is the line segment that starts at the top vertex and ends at the base of the triangle forming a right angle. If we want to find the volume of the of the prism the formula is Ab*h. This is the area of the base, times the height of the prism. This is true because a simple expination of volume is a box filled with stuff. To count how much stuff we have in the box the formula uses layers. Volume is just like a lot of 2 dimential areas stacked on top of each other. So taking the area of the flat base and puting it on top of it self 10 time will give you the same prism thats in the problem. Now we just have to apply the consept. Since the base is a triangle and we need to find the area. The formula is b*h*1/2. Base time height times 1/2. The reason for this is also simlar to area. A triangle is half of a square, so to find the area of a square the formula is L*W. Since a triangle is half of a square you just multipuly it by 1/2. When solved you will get 4*3.5*1/2=7, the area of the base is 7 cm^2. Now appling the topic above we stack the base 10 times, so 7*10=70. In conculstion the volume of the prism would be 70 cm^2.

6 0
2 years ago
How do I add and subtract radicals with no like terms
liq [111]

Most real number arithmetic is pretty vacuous

\sqrt 2 + \sqrt 3 = \sqrt{2} + \sqrt{3}

That's about as good a way as possible to write this particular real number. But it's far from the only way.

(\sqrt 2 + \sqrt 3)^2 = \sqrt{2}^2 + 2\sqrt 2 \sqrt 3 + \sqrt{3}^2 = 5 + 2 \sqrt 6

so

\sqrt 2 + \sqrt 3 = \sqrt{5 + 2 \sqrt 6}

Sometimes you can factor something out and you have a common radical:

\sqrt{32} + \sqrt{128} = \sqrt{2^5} + \sqrt{2^7} = 4 \sqrt{2} + 8 \sqrt{2} = 12 \sqrt{2}

But most of them are vacuous,

3\sqrt{7} + 34 \sqrt{13} = 3\sqrt{7} + 34 \sqrt{13}


8 0
3 years ago
Describe the steps you take to order 5/8(5 on top, 8 on bottom fraction), 0.8, 3/5(3 on top)
sergeinik [125]
First change 0.8 to a fraction which is 4/5. Then find a common denominator between 5/8, 4/5, and 3/5. The common denominator is 40. So then you multiply the numerator by the same number you multiply the denominator by. I'll do 5/8 as an example; to get 40 as your denominator multiply 8 by 5, and then multiply 5 by 5. The fraction you'll get is 25/40. The rest of the fractions are 4/5 - 32/40 and 3/5 - 24/40. Then order them either from smallest to largest (24/40, 25/40, 32/40) or largest to smallest (32/40, 25/40, 24/40).
8 0
3 years ago
7. Please solve by substitution:<br><br>y = 3x + 17<br>y = 2x + 23​
CaHeK987 [17]
3x+17=2x+23

5x=40

40/5=8

x=8
7 0
3 years ago
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