V=V of cube- V pyramid= 8^3- 7^2*8/3=512-49*8/3=512-130,67=381.33 cm^3
Answer: 
Step-by-step explanation:
Transformation rule for dilation:
, where k = scale factor
Given : Scale factor = 
Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)
Vertices after dilation:




Hence, the coordinates of the image if the parallelogram = 
X-2=27
is this a good equations
Answer: Surface area is equal to 200
Volume is equal to 333.33
Step-by-step explanation:
First, let's do surface area.
The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base
The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.
The lateral height is given as 5 cm.
The area of the base is 10(10) = 100.
We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200
.
Now for volume.
The volume of a pyramid is equal to 1/3(area of the base)(height).
We already have the area of the base, which is 100.
The height is given as 10 cm.
Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33
.
Hope this helps!