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4 years ago

Which equation can be used to find the time, t, it takes for the ball to reach the ground?

Mathematics

1 answer:

patriot [66]4 years ago

6 0

Check the picture below, well that picture is using feet, but is pretty much the same curve for meters.

notice, it hits the ground when y = 0, or h(t) = 0, thus

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{12}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{1.8}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ 0=-4.9t^2+12t+1.8\implies -4.9t^2+12t+1.8=0$

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6th grade math, some one help please. Thank you

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2 years ago

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2 years ago

If a household is saving 30% of their total bi-weekly gross pay of $2,051.00, determine how many months it will take to save a 2

Anna35 [415]

Based on the amount saved per week and the down payment of the property, the number of months it will take to save the amount is 46 months.

<h3>How long will it take for the family to save the amount?</h3>

First, find out the amount saved per month:

= (30% x 2,051) x 2 payments a month

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= 281,700 x 20%

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The closing cost is:

= 1.15 x 56,230

= $843.45

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= (56,340 + 843.45) / 1,230.60

= 46 months

Find out more on mortgage downpayments at brainly.com/question/9893085.

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2 years ago

If it takes 1/5 of a gallon of water to fill up a package of water ballons and their are 5 gallons of water in total, Then how m

Debora [2.8K]

Answer:

Step-by-step explanation:

It takes 1/5 of a gallon of water to fill up a package of water balloon

There are 5 gallons of water in total

Therefore the number of packs of balloons that can be filled can be calculated as follows

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3 years ago

**MARKING BRAINLIEST PLEASE HELP**

raketka [301]

Answer:

$\text{1. } v=16t+\frac{h-c}{t},\\\text{2. }90\:\mathrm{ft/s}, \\\text{3. Cannot be determined}$

Step-by-step explanation:

1. The initial equation given to us is $h=-16t^2+vt+c$ . Rearranging the equation to isolate $v$ , we have:

$vt=16t^2+h-c,\\\boxed{v=16t+\frac{h-c}{t}}$

2. Using the equation we rearranged in part 1, we can substitute given values:

$v=16(3)+\frac{131-5}{3},\\v=48+42=\boxed{90\:\mathrm{ft/s}}$

3. We see from our equation in part 1 ( $v=16t+\frac{h-c}{t}$ ) that when $t=0$ , the denominator of our fraction will be equal to 0. Since we cannot divide by 0, the velocity remains undefined and cannot be determined.

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3 years ago