The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

$V=2+\frac{1}{2} t$

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

$V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3$

$V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2} }{1} \\V_{avg}=\frac{1}{2}$

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when $t=1$ is 2.5 sec.

3 0

3 years ago

24=12 18=9 14=7 8=4 6=?

BartSMP [9]

Each pair of numbers gives a value then another value that is 1/2 of the first. So the answer would be

6 = 3

5 0

3 years ago

Sum of all natural numbers from100to300 which are divisible by 4and 5 is

My name is Ann [436]

If $x$ is a number that is both divisible by 4 and 5, then

$\begin{cases}x\equiv0\pmod4\\x\equiv0\pmod5\end{cases}$

4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that $x=20n$ is a solution to the system, where $n$ is any integer. Simply put, any multiple of 20 fits the bill.

Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have $20n=100$ when $n=5$ , so the sum we want to compute is

$\displaystyle\sum_{n=5}^{15}20n=\boxed{2200}$

4 0

3 years ago

Write the 4/5 as a fraction to a percentage​

Write the 4/5 as a fraction to a percentage