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2 years ago

Is (5,50) a solution to the linear system y = 5x + 25 and y = 3x + 35? Explain your reasoning.

Mathematics

2 answers:

elixir [45]2 years ago

8 0

No, because it is not a solution to the linear system shown above

Setler79 [48]2 years ago

3 0

$y = 5x +25~~~~~~~~~~~~~~...(i)\\\\y = 3x +35~~~~~~~~~~~~~~...(ii)\\\\ \text{Substitute (x,y) = (5,50) in both equations.} \\\\y = 5(5) +25 = 25 +25 = 50\\\\y =3(5) +35 = 15 +35 = 50\\\\\text{Hence, (5,50) is a solution to the linear system of equations.}$

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9. Miguel measures 5 kg of rice. One kilogram is approximately equal to 2.2 pounds. Which

Nitella [24]

Answer: 11

Step-by-step explanation:

One kilogram is equal to 2.2 pounds so all you would have to do is multiply 2.2 x 5 and you get 11. :)

8 0

3 years ago

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

3 years ago

Quadrilateral ABCD is inscribed in this circle.

Anna [14]

A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C

so.. C is the difference of all the three angles from 360 or $\bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148$ whatever that is, now, you'll get some value in x-terms

so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture", I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean? well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from 360-x-2x-1-148

so... add them together then and

$\bf \begin{array}{cccclllll}
A&+&C&=&180\\
\uparrow &&\uparrow \\
(2x+1)&+&(360-x-2x-1-148)&=&180
\end{array}$

solve for "x"

6 0

3 years ago

Read 2 more answers

Find the value of x and y

djverab [1.8K]

Answer:

x = 8, y = 27

Step-by-step explanation:

Since both opposite lines are equal in length to each other, these opposite lines are parallel to each other. The top line is parallel and same length as the bottom line and the left and right lines are also parallel and equal in length.

Based on that, the two left side angles must equal 180 and the right side two angles must equal 180.

(2y + 24) + (3y + 21) = 180

That's the same as 2y + 24 + 3y + 21 = 180

Simplify to 5y + 45 = 180

Subtract 45 from both sides

5y = 135

y = 27

(16x - 26) + (9x + 6) = 180

16x - 26 + 9x + 6 = 180

25x - 20 = 180

25x = 200

x = 8

7 0

2 years ago

WILL GIVE BRAINIEST TO WHOEVER'S RIGHT!!!!

Aneli [31]

C. Corresponding Angles Postulate

7 0

3 years ago