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3 years ago

What is the simplified Square root of 41!?!?!??

Mathematics

1 answer:

Nina [5.8K]3 years ago

5 0

Hello there.

<span>Square root of 41!?!?!??

</span><span>6.40312424 </span>

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Does each equation represent exponential decay or exponential growth?

lisov135 [29]

Answer:

1. $H = 5.9(0.82)^{t}$ . Exponential decay function.

2. $y = 0.8(3.6)^{t}$ . Exponential growth function.

3. $f(t) = 0.72(15)^{t}$ . Exponential growth function.

4. $A = \frac{4}{9} (8)^{t}$ . Exponential growth function.

5. $A = (\frac{4}{3})^{t}$ . Exponential growth function.

6. $H = \frac{7}{2} (\frac{5}{6} )^{t}$ . Exponential decay function.

7. g(x) = 0.3(x). Not an exponential function.

Step-by-step explanation:

1. $H = 5.9(0.82)^{t}$ . This is an exponential decay function.

As the value of t increases H-value decreases.

2. $y = 0.8(3.6)^{t}$ . This is an exponential function of growth.

As the value of t increases y-value also increases.

3. $f(t) = 0.72(15)^{t}$ . This is an another example of exponential growth function.

As the value of t increases f(t)-value also increases.

4. $A = \frac{4}{9} (8)^{t}$ . This is again an example of exponential growth function.

As the value of t increases A-value also increases.

5. $A = (\frac{4}{3})^{t}$ . This is again an example of exponential growth function.

As the value of t increases A-value also increases.

6. $H = \frac{7}{2} (\frac{5}{6} )^{t}$ . This is another an example of exponential decay function.

As the value of t increases, H-value decreases.

7. g(x) = 0.3(x). This is a non-exponential function. (Answer)

4 0

3 years ago

Please help :) ...........

ad-work [718]

I think the 3rd one idk wait for someone else to answer go compare

5 0

3 years ago

Write the first five terms of the sequence in which the nth term is

ziro4ka [17]

Answer:

C) 2,6,24,120,720

Step-by-step explanation:

Here the n-th term An = $\frac{(n +2)!}{n + 2}$

A1 is the first term

A1 = (1 + 2)!/(1 + 2)

= 3!/3

A1 = 2

A2 is the second term

A2 = (2 +2)!/(2 +2)

= 4!/4

A2 = (1*2*3*4) /4

A2 = 6

A3 is the third term

A3 = (3 + 2)!/(3 +2)

A3 = 5!/5

A3 = 24

A4 is the fourth term

A4 = (4 + 2)!/(4 + 2)

A4 = 6!/6

A4 = 120

A5 is the fifth term

A5 = (5 + 2)!/(5 +2)

A5 = 7!/7

A5 = 720

Answer: C) 2,6,24,120,720

Thank you.

8 0

2 years ago

You deposit $1,600 in a bank account. The account pays 3% annual Interest compounded monthly. Find the balance after 5 years

kumpel [21]

Step-by-step explanation:

step 1. let's call the amount of money A, the initial amount P, the yearly rate r, the number of compounds per year n.

step 2. A = P(1 + r/n)^(nt)

step 3. A = 1600(1 + .03/12)^((12)(5)

step 4. A = 1600(1.0025)^(60)

step 5. A = $1858.59

8 0

3 years ago

Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extrane

Vinil7 [7]

I'm thinking this is what the problem looks like: $\frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}$ . The first thing to do is to move the $\frac{x}{x-4}$ over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this: $\frac{4-x}{x-4}= -\frac{4}{3}$ . The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.

6 0

2 years ago