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Ivahew [28]
3 years ago
11

What is the simplified Square root of 41!?!?!??

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0
Hello there.

<span>Square root of 41!?!?!??

</span><span>6.40312424 </span>
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ExtremeBDS [4]

Answer:

the question is about the table you have to make a table it is very easy

6 0
3 years ago
Columbia County needs 757 pieces of pipe to repair some water lines. If each box contains 3 pieces of pipe, how many boxes shoul
Dafna1 [17]

Answer:

253 boxes

Step-by-step explanation:

757/3 = 252.33

3 0
3 years ago
Read 2 more answers
What is the ratio 16 to 40 written as a fraction in lowest terms? plz help 50 points
Luda [366]

Answer:- \frac{2}{5}

Step-by-step explanation:

The given ration is 16 :40

In fraction, the above ratio can be written as : \frac{16}{40}

To write the above fraction in lowest terms, we need to divide the numerator and the denominator by the greatest common divisor.

Since, 16=2\times8\\40=5\times8, Hence, 8 is the greatest common divisor of 16 and 40.

Now, divide the numerator and denominator by 8, we get

\frac{16}{40}=\frac{2}{5}

3 0
3 years ago
write a multiplication equation that has a solution of 8 solve the equation Algebraically as likely to prove that your solution
GalinKa [24]
2x = 16
x = 8
Simple as that.
3 0
3 years ago
A bag contains 11 blocks numbered from 1 to 11. Two blocks are selected from the bag at the same time. (order does not matter) L
melamori03 [73]

Answer:

(A) n(Eᶜ)=40

Step-by-step explanation:

The Sample Space for is given as:

(1,2),(1,3),(1,4),(1,5),(1,6),(1,7),(1,8),(1,9),(1,10),(1,11)

(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)

(3,4),(3,5),(3,6),(3,7),(3,8),(3,9),(3,10),(3,11)

(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)

(5,6),(5,7),(5,8),(5,9),(5,10),(5,11)

(6,7),(6,8),(6,9),(6,10),(6,11)

(7,8),(7,9),(7,10),(7,11)

(8,9),(8,10),(8,11)

(9,10),(9,11)

(10,11)

n(S)=55

Event E is the Event that the two numbers are odd.

Therefore: Complement of E will be the event that any of the  two numbers is even.

The Sample Space of the complement of E is:

(1,2),(1,4),(1,6),(1,8),(1,10)\\(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)\\(3,4),(3,6),(3,8),(3,10)\\(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)\\(5,6),(5,8),(5,10)\\(6,7),(6,8),(6,9),(6,10),(6,11)\\(7,8),(7,10)\\(8,9),(8,10),(8,11)\\(9,10)\\(10,11)\\

Therefore:

n(Eᶜ)=40

5 0
3 years ago
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