we have
This is a quadratic equation (vertical parabola) open up
so
the axis of symmetry is the coordinate x of the vertex
<u>Find the vertex of the function</u>
the vertex is the point--------->
so
the axis of symmetry is
therefore
the answer in the attached figure
Answer:
y = -9/7x + 2 is the slope intercept form.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
-3.4, -1.5, 0, 1/2, 8.5, and 8.45
Hope this helped:))
Answer:
85°
Step-by-step explanation:
From the midline theorem.
A segment joining the midpoints of 2 sides of a triangle is parallel to the third side.
Thus KL and GH are parallel lines, thus
∠ H = ∠ KLF = 85° ( corresponding angles )