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3 years ago

What is the interquartile range of the data set? {48, 50, 65, 60, 80, 42, 45, 50, 42, 55, 45}

Mathematics

1 answer:

Tcecarenko [31]3 years ago

6 0

The answer would ether be 16.5 or 10. Sorry, I'm not sure haven't done interquartile range in a little while.

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21. Mickey earned $475 from mowing lawns last summer. He deposited this money in an

Dennis_Churaev [7]

Answer:

first, u need to know the formula for compound interest, which is:

$A = P(1 + \frac{r}{100})^{n}$

where A is the final amount

P- initial amount

r- percent compounded(interest)

and

n- number of years

we have

$A = 475(1 + \frac{3.8}{100})^{4}$

3.8/100 = 0.038

1+0.038 =1.038

1.038^4 = 1.160885573136

475 * 1.160885573136 = 551.4206472396‬

approximately $551.42

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3 years ago

In which region is competition for resources most likely the greatest?

irga5000 [103]

Answer:

In the US for oil. And all around the world

Step-by-step explanation:

5 0

3 years ago

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What is the volume of a shipping cube with dimensions of 3 1/2 feet

son4ous [18]

Answer:

$\large\boxed{V=42\dfrac{7}{8}\ ft^3}$

Step-by-step explanation:

The formula of a volume of a cube:

$V=a^3$

a - edge

We have

$a=3\dfrac{1}{2}\ ft$

Convert to the improper fraction:

$a=\dfrac{3\cdot2+1}{2}=\dfrac{7}{2}\ ft$

Substitute to the formula of a volume:

$V=\left(\dfrac{7}{2}\right)^3=\dfrac{7^3}{2^3}=\dfrac{343}{8}=42\dfrac{7}{8}\ ft^3$

7 0

3 years ago

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Is this a polygon Yes or no

Kobotan [32]

No its not a polygon.

It has a curve where as a polygon is a plane figure with at least three straight sides and angles

Thanks for the help xoxoate!

6 0

2 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 430 green peas and 155 yellow peas. Use a 0.05

Dimas [21]

Answer:

the null and alternative hypothesis are

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

Test statistic is 1.416.

P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level

At 0.05 significance we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

Step-by-step explanation:

Let p be the proportion of offspring peas will be yellow. Then,

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

test statistic can be calculated as

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of yellow offspring peas ( $\frac{155}{155+430} =0.265$
p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)

N is the sample size (585)

Test statistic is z= $\frac{0.265-0.24}{\sqrt{\frac{0.24*0.76}{585} } }$ ≈ 1.416.

Using z-table, we can find that P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05

We can conclude that at 0.05 significance we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

6 0

3 years ago