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zhenek [66]
3 years ago
13

Solve the following quadratic by completing the square. y = x2 - 6x + 7

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

x = 5  or   x = 1

Step-by-step explanation:

 x² - 6x + 7 = 0

x² - 6x = -7

x² - 6x + 9 = -7 + 9      1/2 of the x term than square it and add it the both sides.

(x - 3)(x - 3) = 2

( x -3)² = 2

\sqrt{(x - 3)^2 = \sqrt{2}

(x -  3) = ± 2

x - 3 = 2  or  x - 3 = -2

x = 5     or  x = 1

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The sum of the roots of 3x 2 + 11x - 4 = 0 is<br><br> -11/3<br> -4/3<br> 11/3<br> 4/3
givi [52]

Answer:

The correct option is 1.

Step-by-step explanation:

If a quadratic equation is defined as

ax^2+bx+c=0             .... (1)

Then the sum of the roots is -b/a and the product of roots is c/a.

The given equation is

3x^2+11x-4=0          ... (2)

From (1) and (2) we get a=3, b=11 and c=-4.

The sum of roots is

\frac{-b}{a}=-\frac{11}{3}

The sum of roots is -\frac{11}{3}.

Therefore the correct option is 1.

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