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3 years ago

14

Which expression is equal to (7 times 2)times 2

1 answer:

Lady bird [3.3K]3 years ago

7 0

The answer is 28. 7x2=14 and then 14x2=28. Remember PEMDAS

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What is 608 + 17.25?

adelina 88 [10]

Answer:

625.25

Step-by-step explanation:

the answer is 625.25

5 0

2 years ago

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a shopkeeper buys coffee at 4.20 per kg and sells it at 63 cents per 100 g Calculate his profit percentage

Bingel [31]

420 cents for 1000 g. So 42 cents for 100 g (i crossed multiplied). %profit=63-42/42 *100=50%

7 0

2 years ago

The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th

makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 $e^{kt}$

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070 $e^{3k}$

$\frac{9000}{4070}$ = $e^{3k}$

$\frac{900}{407}$ = $e^{3k}$

<u><em>Taking natural logarithm on both sides, we get:</em></u>

$ln\frac{900}{407}$ = $ln(e^{3k})$

$ln\frac{900}{407}$ = 3k ln<em>e</em>

ln<em>e</em>=1

$ln \frac{900}{407}$ = 3k

or k = $\frac{1}{3}$ $ln\frac{900}{(407)}$

k = $\frac{1}{3}$ (0.7936)

<em>k = 0.2645</em>

<em />

7 0

2 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago

How do u combine like terms

velikii [3]

If the equation is let's say 3x+ 7 +4x to combine like terms, you would take 3x and 4x since they both have x. You wouldn't take the 7 since it doesn't have and x like the other numbers. 3x +4x = 7x so your new equation would be 7x + 7.

6 0

2 years ago

Read 2 more answers