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Vaselesa [24]
4 years ago
5

What is the quotient (3x^4-4x^2+8x-1)/(x-2)?

Mathematics
2 answers:
Evgen [1.6K]4 years ago
7 0

Answer:

3x³+ 6x²+ 8x + 24 r. 47

Step-by-step explanation:

3x^4-4x^2+8x-1/(x-2)

Bezzdna [24]4 years ago
5 0

Answer:

3x^3 + 6x^2 +8x +24

Step-by-step explanation:

I hope this helps!

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What is 713.49 written in standard form?
Nuetrik [128]

Answer:     Seven hundred thirteen point forty-nine.

Step-by-step explanation:    Hope this helps ;)

4 0
3 years ago
If x = 5 and 5 = y, then x = y
garri49 [273]
You are right. Transitivity means, that:
if a = b and b = c, then a = c
(here a = x, b=5 and c = y).
5 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
2. My bank account contains pesos 3021 and make monthly withdrawals of pesos 78 for 12 months. What is my new bank balance.
Agata [3.3K]

Answer:

ok I will try solve your problem. good luck

Step-by-step explanation:

a. known: Bank balances : 3021 pesos

monthly withdrawals: 78 pesos

months of withdrawal: 12 months

b. asked: new bank balance?

c. equation: New bank balance= bank balance - ( monthly withdrawals X months of withdrawal)

d. New bank balance: 3021- (78x12)

= 3021 - 936

= 2085 pesos

e. my new bank balance is 2085 pesos.

4 0
1 year ago
Rounding 552,945 with the first 5 underlined
NISA [10]
553,000 is the answer for rounding up
8 0
3 years ago
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