Answer:
about 5 years 6 months
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 5%/100 = 0.05 per year,
then, solving our equation
t = 178.25 / ( 650 × 0.05 ) = 5.4846
t = 5.4846 years
The time required to
accumulate simple interest of $ 178.25
from a principal of $ 650.00
at an interest rate of 5% per year
is 5.4846 years (about 5 years 6 months).
Answer:
she bought 70 shares of the $15 shares
she bought 20 shares of the $20 shares
Step-by-step explanation:
this would be solved using simultaneous equation
let a = $15 shares
b = 20 shares
a + b = 90 equation 1
15a + 20b = 1450 equation 2
Multiply equation 1 by 15
15a + 15b = 1350 equation 3
subtract equation 3 from equation 2
5b = 100
b = 20
substitute for b in equation 1
20 + a = 90
a = 70
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.
Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.
Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7
Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18
Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.
Answer: 37,39,41,43
<em><u>Polynomials in standard form:</u></em>
<em><u>Solution:</u></em>
Standard form of polynomials: terms are ordered from biggest exponent to lowest exponent
<em><u>Option A:</u></em>
The above is a polynomial
Where, largest exponent is arranged first
Therefore, it is standard form of polynomial
<em><u>Option B</u></em>
Here, exponents are from greatest to least
Therefore, it is standard form of polynomial
<em><u>Option C</u></em>
Here, "t" is a variable. The first term has largest degree
Therefore, it is standard form of polynomial
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