3 years ago

What is the answer for this problem ?

Mathematics

1 answer:

baherus [9]3 years ago

8 0

The 3rd one is the answer

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What is the remainder when 599 is divided by 9?

Schach [20]

$599=540+59=540+54+5=60(9)+6(9)+5$
$\implies\dfrac{599}9=66+\dfrac59$

so the remainder is 5.

3 0

3 years ago

Read 2 more answers

–9x + 9y = 9 y = –7 ( , )

Y_Kistochka [10]

Answer:

x=-8

(-8,-7)

Step-by-step explanation:

–9x + 9y = 9

–9x + 9(-7) = 9 (y=-7)

-9x-63=9

Both side +63

-9x=63+9

-9x=72

Both side divide -9

x=-8

y=-7

(-8,-7)

6 0

3 years ago

2n-7/3 = 15 solve for n

WITCHER [35]

$2n- \frac{7}{3} =15$
$2n- \frac{7}{3} =15$ common denominator is 3
$3(2n- \frac{7}{3} )=3*15$ distributhing 3 through parantheses
$3*2n- \frac{3*7}{3}=3*15$
$3*2n-7=3*15$
$6n-7=45$ add7
$6n=45+7$
$6n=52$ divide by 6
$n= \frac{52}{6}$ simplify
$n=8 \frac{2}{3}$ ⇒ $\frac{26}{3}$

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3 years ago

For mutually exclusive events we can use the ____ Principle of Counting.

leonid [27]

Fundamental principle of counting

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3 years ago

Simplify (3-3)/√3=0

zalisa [80]

Answer:

its 0 anyways lol

Step-by-step explanation:

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3 years ago