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Lerok [7]
3 years ago
8

Y - (-9) = 8? I am confused

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:

y = -1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

y - (-9) = 8

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Simplify:                                                                                                             y + 9 = 8
  2. [Subtraction Property of Equality] Subtract 9 on both sides:                        y = -1
Yuki888 [10]3 years ago
4 0

Answer:

y = -1

Step-by-step explanation:

y - ( - 9) = 8

y + 9 = 8

y = 8 - 9

y = -1

- ( - turns to + because you are subtracting a negative number

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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user100 [1]
The correct answer is:

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3 years ago
This is the problem<br> Dan says 3/5 Is the same as 3.5. Is he correct? Explain
lesya692 [45]

<u><em>Answer:</em></u>

He is not correct


<u><em>Explanation:</em></u>

The first number is \frac{3}{5}

We can note that the numerator is less than the denominator. This means that the given fraction is less than 1

In decimal form, \frac{3}{5} is equal to 0.6


The second number is 3.5

We can note that this number is greater than 1.


This means that the two numbers are not equal


Hope this helps :)

4 0
3 years ago
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1/2 ÷ 1/2 I am kind of confused
N76 [4]

Answer:

1

Step-by-step explanation:

\huge\frac{1}{2}  \div  \frac{1}{2}  =  \frac{1}{2}   \times   \frac{2}{1}   = 1

3 0
3 years ago
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Is that the correct answer for it please help me. I want to past my ecam
Eduardwww [97]

Answer:

No answer is be 28%

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Step-by-step explanation:

4 0
2 years ago
F) m(4+p) +p(3 + m)
ipn [44]

\bold{\huge{\pink{\underline{ Solutions }}}}

  • <u>Here</u><u>, </u><u> </u><u>we </u><u>have </u><u>to </u><u>expand </u><u>the </u><u>given </u><u>expression</u><u>s</u><u> </u><u>and </u><u>simplify </u><u>each </u><u>one </u><u>of </u><u>them</u>

<h3><u>Solution</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

\bold{m(4 + p) + p( 3 + m) }

\sf{4×m + m× p + p×3+ m × p}

\sf{4m + mp + 3p + mp }

\bold{\red{ 2mp + 4m + 3p}}

Hence, Your answer is 2mp + 4m + 3p

<h3><u>Solution </u><u>2</u><u> </u><u>:</u><u>-</u></h3>

\bold{4r(3+ 4p) + 3p( 8 - r) }

\sf{4r× 3+ 4r × 4p + 3p× 8 - 3p × r}

\sf{12r + 16rp + 24p - 3rp }

\sf{12r + 24p + 13rp }

\bold{\red{13rp + 24p + 12r }}

Hence, your answer is 13rp + 24p + 12r

<h3><u>Solution </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

\bold{(3 + 2h)(5 + 3h )}

\sf{3(5 + 3h) + 2h(5 + 3h }

\sf{15 + 9h + 10h + 6h² }

\sf{15 + 19h + 6h²}

\bold{\red{6h² + 19h + 15}}

Hence, your answer is 6h² + 19h + 15

<h3><u>Solution </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

\bold{(3 + 4y)(5y - 1 ) }

\sf{3(5y - 1 ) + 4y(5y - 1) }

\sf{15y - 3 + 20y² - 4y }

\sf{11y - 3 + 20y²}

\bold{\red{20y² + 11y - 3 }}

Hence, your answer is 20y² + 11y - 3

<h3><u>S</u><u>olution </u><u>5</u><u> </u><u>:</u><u>-</u></h3>

\bold{(2n - 3p )(3p - 2m ) }

\sf{2n(3p - 2m) -3p(3p - 2m) }

\sf{ 6np - 4nm - 9p² + 6mp }

\bold{\red{- 9p² - 6mp - 4nm + 6np }}

Hence, your answer is - 9p² - 6mp - 4nm + 6np

7 0
2 years ago
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