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irina1246 [14]
3 years ago
12

Does anyone on this website know geometry?? please help........................

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

Step-by-step explanation:

12 six times

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Someone knows this one? help me please help help :(<br>thank you so much​
noname [10]

Answer:  d

<u>Step-by-step explanation:</u>

KE=\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=\bigg(\dfrac{2}{m}\bigg)\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=v^2\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=\sqrt{v^2}\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=v

5 0
3 years ago
Pls I need help with the top one
Likurg_2 [28]

about empty will be 2/19

about half will be 2/7, 2/5 & 6/11

about full will be 10/12

7 0
3 years ago
Options for first blank: V=PR V=(PR)^(1/2) V=P^2R Options for second blank 16 5 4
oksano4ka [1.4K]

Answer:

The formula to find the voltage is:

v=\sqrt{P*R}

And the voltage is 4 volts

Step-by-step explanation:

To get the equation of voltage you need to isolate v in one side of the equation. In order to do that, you need to remove the divisor/denominator and its square. How will you do that?

First, multiply both sides with R:

P*R=\frac{v^{2} }{R} *R

That would result into removing the divisor R from the right side of the equation:

P*R=v^{2}

Next, square-root both sides:

\sqrt{P*R} =\sqrt{v^{2} }

That would result in removing the square of v from the right side of the equation:

\sqrt{P*R} =v

Thus we get the equation, v=\sqrt{P*R}.

To find out the voltage, simply replace R with 32 and P with 0.5

v=\sqrt{0.5*32}

r=\sqrt{16}

r=4

Thus, the voltage is 4 volts.

4 0
3 years ago
Can someone help me ?
Leni [432]

Answer:

d

Step-by-step explanation:

if she connects it to any other point angle would be more the 30 degree

6 0
3 years ago
Read 2 more answers
Please help with question #3!
Dmitry [639]

Answer:

  e.  1/(49n² +7n)

Step-by-step explanation:

\dfrac{(7n-1)!}{(7n+1)!}=\dfrac{(7n-1)!}{(7n+1)(7n)(7n-1)!}=\dfrac{1}{(7n+1)(7n)}\\\\=\dfrac{1}{49n^2+7n}

5 0
3 years ago
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