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AVprozaik [17]
3 years ago
8

What are the zeros of the quadratic function? f(x)=2x^2+x−3

Mathematics
2 answers:
ELEN [110]3 years ago
7 0

Answer:

x = 1  and x = - \frac{3}{2}

Step-by-step explanation:

2x^2+x−3 = 0

(2x + 3)(x - 1) = 0

2x + 3 = 0;x = - 3/2

x - 1 = 0; x = 1

x = 1  and x = - 3/2

Vertex: 2x^2+x-3: Minimum: (-1/4,-25/8)

Brums [2.3K]3 years ago
4 0

Answer:

x = 1  and x = - 3/2

Step-by-step explanation:

the zeros of the quadratic function when f(x) = 0

So

2x^2+x−3 = 0

Factor:

2x^2+x−3 = 0

(2x + 3)(x - 1) = 0

2x + 3 = 0;x = - 3/2

x - 1 = 0; x = 1

Answer:

x = 1  and x = - 3/2

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