Question

What are the zeros of the quadratic function? f(x)=2x^2+x−3

Answer 1

Answer:

x = 1  and x = - $\frac{3}{2}$

Step-by-step explanation:

2x^2+x−3 = 0

(2x + 3)(x - 1) = 0

2x + 3 = 0;x = - 3/2

x - 1 = 0; x = 1

x = 1  and x = - 3/2

Vertex: 2x^2+x-3: Minimum: (-1/4,-25/8)

Answer 2

Answer:

x = 1  and x = - 3/2

Step-by-step explanation:

the zeros of the quadratic function when f(x) = 0

So

2x^2+x−3 = 0

Factor:

2x^2+x−3 = 0

(2x + 3)(x - 1) = 0

2x + 3 = 0;x = - 3/2

x - 1 = 0; x = 1

Answer:

x = 1  and x = - 3/2