Answer:
Number 2 is 3:4.
Number 1 is d.
Step-by-step explanation:
Boxers and collies added together gives you 12:16. Divide them both by 4 and you get 3:4.
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The number of student in class 4 (6) divided by the total number of kids in the entire class (18) gives you 0.33333333333. Multiply that by 100 and it gives you 33.3333333333. As a percentage it is 33 1/2 %
You find area by multiplying base and height.
The formula is A=bh
so 100=25h
25 times 4 is 100
100=25*4
4cm is your answer
Answer:
Step-by-step explanation:
B(2,10); D(6,2)
Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)
Rhombus all sides are equal.
AB = BC = CD =AD
distance = √(x2-x1)² + (y2- y1)²
As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x
A(X,0)
AB = AD
√(2-x)² + (10-0)² = √(6-x)² + (2-0)²
√(2-x)² + (10)² = √(6-x)² + (2)²
√x² -4x +4 + 100 = √x²-12x+36 + 4
√x² -4x + 104 = √x²-12x+40
square both sides,
x² -4x + 104 = x²-12x+40
x² -4x - x²+ 12x = 40 - 104
8x = -64
x = -64/8
x = -8
A(-8,0)
Let C(a,b)
M is AC midpoint
(-8+a/2, 0 + b/2) = M(4,6)
(-8+a/2, b/2) = M(4,6)
Comparing;
-8+a/2 = 4 ; b/2 = 6
-8+a = 4*2 ; b = 6*2
-8+a = 8 ; b = 12
a = 8 +8
a = 16
Hence, C(16,12)
Answer:
x = 2
Step-by-step explanation:
8(4-x) = 7x + 2
1) Distribute : 32 - 8x = 7x + 2
2) Subtract 32 : -8x = 7x - 30
3) Subtract 7x : -15x = -30
4) Divide 15 : x = 2 :)
In both cases,
(as a consequence of the interesecting secant-tangent theorem)
So we have
10.
(omit the negative solution because that would make at least one of AB or AD have negative length)
11.
(again, omit the solutions that would give a negative length for either AB or AD)
