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JulijaS [17]
3 years ago
9

Find the slope of the line running through these two points (-4,5) and (8,-3)

Mathematics
2 answers:
Artemon [7]3 years ago
8 0

Answer:

The slope is

\frac{-3-5}{8-(-4)} =\frac{-8}{8+4} =\frac{-8}{12} =-\frac{2}{3}

Step-by-step explanation:

Evgen [1.6K]3 years ago
5 0

The slope the line that passes through the given points is \bold{\frac{-3}{4}}

<u>SOLUTION: </u>

Given, two points are (- 4, 5) and (8, -3). We have to find the slope of a line that passes through the above given two points.

We know that, slope of a line that pass through \bold{(x_1, y_1) \text{ and } (x_2, y_2) \text{ is given by } \mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}}

Here, in our problem, x_{1}=-4; y_{1}=5 \text { and } x_{2}=8; y_{2}=-3

Now, slope \bold{m=\frac{-3-5}{8-(-4)}=\frac{-8}{8+4}=\frac{-8}{12}=\frac{-3}{4}}

Hence, the slope is \frac{-3}{4}

<em>The following are the steps in calculating the slope of a straight line:</em>

  • Step One: Identify two points on the line.
  • Step Two: Select one to be (x_1, y_1) and the other to be (x_2, y_2)
  • Step Three: Use the slope equation to calculate slope.
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two buses leave towns 604 mi apart at the same time and travel toward eachother. One bus travels 9 mi/h faster than the other on
muminat

Answer:

s = 71 mph, and s+9 = f = 80 mph

Step-by-step explanation:

The distances the two busses travel add up to 604 mi.

Letting f be the faster speed and s the slower.  Then f = s + 9 (mph).

Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi.  Solve this for s:

4s + 36 + 4s = 604 mi, or 8s = 568.  Finally, s = 71 mph, and s+9 = f = 80 mph.


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ANSWER THIS AND ILL LOVE YOU <br><br> find angles FAB and BAC
jeyben [28]

Answer:

m<FAB = 75°

m<BAC = 105°

Step-by-step explanation:

First, find the value of x.

(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)

Solve for x

13x - 3 = 3x + 2 + 55

13x - 3 = 3x + 57

Collect like terms

13x - 3x = 57 + 3

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Divide both sides by 10

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Plug in the value of x

m<FAB = 13(6) - 3 = 78 - 3

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m<BAC = 180 - 75 (substitution)

m<BAC = 105°

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