Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.
Step-by-step explanation:
Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.
c= 100 (0.99988)^t
c =100 (0.99988)^4
c = 100 x 0.999520086
c= 99.95200864 ≅99.95 grams (rounded)
The amount of carbon-14 remaining after 4 years is 99.95 grams.
Feel free to ask for more if needed or if you did not understand something.
we know that given terms were i geometric progression.
which means common ratio is same between two consecutive terms .
here we have 8,40,200,1000.
we know that common ratio =second term/first term =40/8=5.
so each and every terms is multiplied by 5 to get next term for this series the term after 1000 is 5000 =1000*5.
in part b we have another series which is having common ratio of -2.
so we need to multiply with -2 to find next term.
80*(-2)=-160.
for part c the common ratio is -2 .
so we need to multiply with -2 *previous term =-2*16 =-32.
|–2x| = -6
=> 2x = 6
=> x = 3
and,
=> 2x = -6
=> x = -3.
Two points, one at negative 3 and one at 3.
Answer:
i think its the 2 choice hope this help's
Step-by-step explanation:
Idk.................................................................... sorry
