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Elodia [21]
3 years ago
15

¿Cual es el monto producido por un capital de 7200 colocados al 4% anual durante 3 años y 4 meses ?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

3 años 4 meses

 4   primer año

 4    segundo año

4    tercer año pero nos falta 4 meses  4/12 = .33333  esto x 4 los meses =    1.3333

____

13.3333

7200 * .133333= 959.9976  por aproximacion son 960

7200+960 = 8160 Es el monto producido

Opcion C

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Am I right idk could some explain. This to me.
Marysya12 [62]

It is 100 times smaller because 1.95x100=195 !!!

7 0
3 years ago
Hi need help early giving out 98 points<br> Thank you : )
Setler [38]

Answer:

1)f(x)=2(3)^x

2)f(x)=10(2)^x

3)Graph attached

4) Amber will have 192 and 3145728 shares on day 3rd and 10th respectively

Ben will have 54 and 118,098 shares on day 3rd and 10th respectively

Carter will have 80 and 10240 shares on day 3rd and 10th respectively

5)the graph has moved 45 unit up

6)Amber's posts will travel fastest

7)Amber' function

Step-by-step explanation:

1)

Ben shares posts with two friends and then they share with 3 more everyday, so her the growth rate is 3

f(x)=2(3)^x

x=number of days

2)

Carter shares posts with ten friends and then they share with 2 more everyday, so her the growth rate is 2

f(x)=10(2)^x

x=number of days

3)

Graph attached contain graph's of following

Ben's f(x)=2(3)^x in red

Carter's f(x)=10(2)^x in blue

Amber's f(x)=3(4)^x in green

4)

Finding how many shares each student will get on day 3 and day 10:

For Amber:

substituting x=3,

f(x)=3(4)^3

     = 192

Now substituting x=10,

f(x)= 3(4)^10

     = 3145728

Amber will have 192 and 3145728 shares on day 3rd and 10th respectively

For Ben:

substituting x=3,

f(x)=2(3)^3

     = 54

Now substituting x=10,

f(x)= 2(3)^10

     = 118,098

Ben will have 54 and 118,098 shares on day 3rd and 10th respectively

For Carter:

substituting x=3,

f(x)=10(2)^3

     = 80

Now substituting x=10,

f(x)= 10(2)^10

     = 10240

Carter will have 80 and 10240 shares on day 3rd and 10th respectively

5)

If Amber's graph changes to

f'(x)=3(4)^x +45

then as per translation, it means the graph has moved 45 unit up from original position as shown in attached graph

original f(x)=3(4)^x in green

translated f'(x)=3(4)^x +45 in blue

6)

In exponential function the base of function effects the growth and in given cases of Amber, Ben and Carter; base of Amber's function is greatest i.e 4 other two have 2 and 3.

So Amber's posts will travel fastest

7) A post with fewer friends initially and then more shares like Amber. Because at the end of the day the growth rate is important and as explain above the number of shares i.e base of exponential function is important.

Hence for more shares and likes Amber' function is the best choice !

3 0
3 years ago
PLEASE HELP I DON'T UNDERSTAND! A florist is making regular bouquets and mini bouquets. The florist has 118 roses and 226 peonie
Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m  = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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