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Gre4nikov [31]
3 years ago
10

Find the missing length . Leave your answers in simplest radical form

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

A^2 + B^2 = C^2

x^2 + 9^2 = (SQRT 226)^2

x^2 + 81 = 226

x^2 = 145

x = SQRT 145

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1. What is the circumference of a circle with a radius of 3? (1 point)
4vir4ik [10]
1. 6 \pi
This is because 
c=  \pi d \\ 
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2. 9 \pi
because 
A= \pi  r^{2}  \\ 
A =  \pi (3)^{2}  \\ 
A = 9 \pi

3. 4 \pi
C=  \pi d \\ 
C= 4 \pi

4. 4 \pi
A = \pi r^{2} \\ A = \pi (2)^{2} \\ A = 4 \pi

Can't really answer the last 2 w/o the figures

7 0
4 years ago
Question 5(Multiple Choice Worth 1 points)
Roman55 [17]

Answer:

x <= 5 is the answer

Step-by-step explanation:

Because the arrow is pointinng the direction of the color

7 0
3 years ago
Harold uses the binomial theorem to expand the binomial (3x^5 - 1/9y^3)^4
riadik2000 [5.3K]
<h3><em>The complete question:</em></h3>

<u><em> </em></u><u>Harold uses the binomial theorem to expand the binomial </u>(3x^5 -\dfrac{1}{9}y^3)^4<u />

<u>(a)    What is the sum in summation notation that he uses to express the expansion? </u>

<u>(b)    Write the simplified terms of the expansion.</u>

Answer:

(a). (3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}( -\dfrac{1}{9}y^3)^k $$

(b).(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}

Step-by-step explanation:

(a).

The binomial theorem says

(x+y)^n=$$\sum_{k=0}^{n}  \binom{n}{k}x^{n-k}y^k $$

For our binomial this gives

\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n}  \binom{4}{k}x^{4-k}y^k $$}

(b).

We simplify the terms of the expansion and get:

$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}y^k $$= \binom{4}{0}(3x^5)^{4-0}(-\dfrac{1}{9}y^3 )^0+\binom{4}{1}(3x^5)^{4-1}(-\dfrac{1}{9}y^3 )^1+\\\\\binom{4}{2}(3x^5)^{4-2}(-\dfrac{1}{9}y^3 )^2+\binom{4}{3}(3x^5)^{4-3}(-\dfrac{1}{9}y^3 )^3+\binom{4}{4}(3x^5)^{4-4}(-\dfrac{1}{9}y^3 )^4

$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}(-\frac{1}{9}y^3 )^k $$= (3x^5)^{4}+4(3x^5)^{3}(-\frac{1}{9}y^3 )+6(3x^5)^{2}(-\frac{1}{9}y^3 )^2+\\\\4(3x^5)(-\frac{1}{9}y^3 )^3+(-\frac{1}{9}y^3 )^4

\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}   }

3 0
3 years ago
NEED HELP NOW 100 POINTS NEED 1 PARAGRAPH EACH EXPLAINING QUESTIONS 9 AND 10 WILL MARK BRAINLIEST ANSWER!!!
amm1812
9) Area of Figure = Area of rectangle + area of triangle

A = 17 * 22 + (1/2 * 12 * 19)

A = 374 + 114

A = 488 cm²

10) Area of Figure = Area of rectangle + area of triangle

A = 8 * 4 + (1/2 * 3*4)
A = 32 + 6

A = 38 cm²

Hope this helps!
7 0
4 years ago
Read 2 more answers
Nathan bought 4 pounds of chicken for $8. How many pounds can he buy for $20? *
seraphim [82]

Answer:

The correct answer is 10 pounds of chicken

Step-by-step explanation:

First you do 8 divided by 4 to equal the unit price of 1 pound of chicken for 2 dollars then you do 20 divided by 2 to equal 10 pounds of chicken for 20 dollars

HAVE A GOOD DAY!

5 0
3 years ago
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